A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
How would I solve this?
anonymous
 one year ago
How would I solve this?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \frac{(xh)^2}{a^2}\frac{(yk)^2}{b^2} \longrightarrow \frac{(x(4))^2}{3^2} \frac{(y(3))^2}{4^2}=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0On the left you have the equation of a hyperbola, and the right arrow is what the equation of the hyperbola translates into, which is your function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To find the foci and vertices, we need to identify what the center is. center : \((h,k)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's wrong, sorry.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now the foci lie along the horizontal transverse axis, what you know as the major axis. Therefore to find their location, we use the formula \[(h+c),k ~,~ (hc),k~~, c^2=a^2+b^2 \longrightarrow c=\sqrt{a^2+b^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To find the vertices, you use the equation \[{(h+a),k} ~,~ {(ha),k}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, c = 5. You are right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you, could you help me with one more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks :) This is like the opposite I guess.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.