anonymous
  • anonymous
How would I solve this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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Jhannybean
  • Jhannybean
\[\large \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} \longrightarrow \frac{(x-(-4))^2}{3^2} -\frac{(y-(-3))^2}{4^2}=1\]
Jhannybean
  • Jhannybean
On the left you have the equation of a hyperbola, and the right arrow is what the equation of the hyperbola translates into, which is your function

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Jhannybean
  • Jhannybean
To find the foci and vertices, we need to identify what the center is. center : \((h,k)\)
anonymous
  • anonymous
That's wrong, sorry.
anonymous
  • anonymous
hmm
Jhannybean
  • Jhannybean
?...
anonymous
  • anonymous
-4,-3
Jhannybean
  • Jhannybean
Good.
Jhannybean
  • Jhannybean
Now the foci lie along the horizontal transverse axis, what you know as the major axis. Therefore to find their location, we use the formula \[(h+c),k ~,~ (h-c),k~~, c^2=a^2+b^2 \longrightarrow c=\sqrt{a^2+b^2}\]
anonymous
  • anonymous
c=5
anonymous
  • anonymous
(1, -3,) (-9,-3)
Jhannybean
  • Jhannybean
To find the vertices, you use the equation \[{(h+a),k} ~,~ {(h-a),k}\]
anonymous
  • anonymous
(-1, -3) (-7,-3)
anonymous
  • anonymous
?
Jhannybean
  • Jhannybean
Yes, c = 5. You are right.
anonymous
  • anonymous
Thank you, could you help me with one more?
Jhannybean
  • Jhannybean
Sure, i can try
anonymous
  • anonymous
Thanks :) This is like the opposite I guess.
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anonymous
  • anonymous
@Jhannybean

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