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anonymous

  • one year ago

Geometry Writing Assignment: Angles Each problem is worth 5 points Total Points: 50 Use the image below and answer questions 1-5. Show all your work. 28° 47° 65° E D C B A 1. ∠m+∠AEB+m<CED 2. 2m<AEC 3. M<AED-m<BEC 4. M ∠AEC+3m∠ BEC 5.1/2m<BED +4<AEB

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @Owlcoffee @mathway @JadedInsomniac @jamaicabeckford @jamesr @Jdosio @jane11509

  3. anonymous
    • one year ago
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    |dw:1438464005525:dw|

  4. anonymous
    • one year ago
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    What is the measure of ∠AEB?|dw:1438464194239:dw|

  5. anonymous
    • one year ago
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    Add it with m∠CED. He're the ∠CED|dw:1438464246683:dw|

  6. anonymous
    • one year ago
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    Can you answer it?

  7. anonymous
    • one year ago
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    its confusing

  8. anonymous
    • one year ago
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    The measure is just the numbers you see.

  9. anonymous
    • one year ago
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    okay thanks

  10. anonymous
    • one year ago
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    Add them together. |dw:1438464471661:dw|

  11. anonymous
    • one year ago
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    Can you now add them together? I already encircled the angles for you.

  12. anonymous
    • one year ago
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  13. anonymous
    • one year ago
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    That's for number 1. -_-

  14. Owlcoffee
    • one year ago
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    So, I'll give you the example with the fouth part of this excercise. \[m \angle AEC + 3 m \angle BEC\] I'll try to mention it from the groundings, but I will suppose you have a certain level of geometry in you knowledge repertoire. The expression "\(m \angle \) " Does mean "Measure of angle" and is preceded by the angle in question. So, we will observe the diagram and pick out the angles we need, in this case \(\angle AEC \) and \(\angle BEC\), but thing is, that \(\angle AEC \) is composed by other two angles, which means that we can express it as a sum of angles, being these angles \(\angle AEB \) and \(\angle BEC\), and we notate it: \(\angle AEC = \angle AEB+ \angle BEC\) Now, let's go back to the excercise: \[m \angle AEC + 3 m \angle BEC\] And let's start replacing the information we have just deduced, which is: \(\angle AEC = \angle AEB+ \angle BEC\) and this must also mean that their measures also have that same composition: \(m\angle AEC = m\angle AEB+ m\angle BEC\) so let's replace it: \[(m \angle AEB + m \angle BEC) + 3 m \angle BEC\] Now, looking at the diagram we will pick out the measures of \(\angle AEB \) and \(m\angle BEC\) which are "\(m\angle BEC = 47\)" and \(m\angle AEB = 28 \) Therefore, the measures will be: \[m \angle AEB + m \angle BEC + 3m \angle BEC \rightarrow (28) + (47)+3(47)\] And nw, all you have to do is focus on this: \[(28) + (47)+3(47)\]

  15. anonymous
    • one year ago
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    thanks !!

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