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anonymous

  • one year ago

Simplify the rational expression please help and explain with me?√125h^4 choices a.5h^2√5 b.25h^2√5 c.h√62.5 d.5√5h^4

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  1. anonymous
    • one year ago
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    I have a idea what to do but the power of 4 makes me get lost,

  2. campbell_st
    • one year ago
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    look at the problem this way \[\sqrt{5 \times 25 \times h^2 \times h^2}\] which terms can you take the square root of..?

  3. anonymous
    • one year ago
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    25 would be 5 and wouldn't h^2 and h^2 be crossed out? still new to this

  4. campbell_st
    • one year ago
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    well 25 to 5 is correct h^2 goes to h when you take the square root so the problem can be rewritten as \[\sqrt{5} \times \sqrt{25} \times \sqrt{h^2} \times \sqrt{h^2} = \sqrt{5} \times 5 \times h \times h\] just simplify it

  5. anonymous
    • one year ago
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    you get the same as you had before= right?if to solve it

  6. campbell_st
    • one year ago
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    well it has been simplified now... all you need to do is tidy up the answer so it matches one of your choices

  7. anonymous
    • one year ago
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    and how would you go about doing this?

  8. campbell_st
    • one year ago
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    ok... in bits \[\sqrt{5} \times 5 = 5 \sqrt{5}\] what does \[h \times h =\]

  9. anonymous
    • one year ago
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    25 and h^2?

  10. campbell_st
    • one year ago
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    h^2 is correct so its now \[5 \times \sqrt{5} \times h^2 = 5 \times h^2 \times \sqrt{5}\] rememeber when muliplying, the order doesn't matter

  11. anonymous
    • one year ago
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    can you square root 5 though is that even possible?

  12. campbell_st
    • one year ago
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    ok... the solution in correct but in algebra will normally don't write the multiplication signs when writing a term... so how can you rewrite \[5 \times h^2 \times \sqrt{5}\]

  13. anonymous
    • one year ago
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    so wouldn't the answer be 5h^2√5?

  14. campbell_st
    • one year ago
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    just write it without the multiplication signs

  15. campbell_st
    • one year ago
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    that's correct

  16. phi
    • one year ago
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    \( \sqrt{5} \) is theoretically possible... but it is not a "nice" number 2.236067977499789696409173668731276235440618359611525724270897245410520925637804899414414408378782275... it goes on forever (ugh!)

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