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superhelp101
 one year ago
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superhelp101
 one year ago
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superhelp101
 one year ago
Best ResponseYou've already chosen the best response.0When an atom releases a beta particle, the mass number decreases by one. the mass number increases by one. the atomic number increases by one. the atomic number remains the same.

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1what is the isotopic symbol for a beta particle?

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438469062312:dw

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1now suppose an atom of carbon14 undergoes beta decay

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1\[^{14}_{6}C \rightarrow ^0_{1} \beta + ^A_Z?\]

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1in nuclear reactions, the \(total\) atomic number must be conserved, and the \(total\) mass number must also be conserved

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1since the total atomic number \(must\) add up to 6, what must the other particle be to make the bottom "equation" true?

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1since those are atomic numbers, what particle has an atomic number of 7?

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1and what about the mass number?

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.0nitrogen atomic mass 14.00674

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1you don't need the average mass of nitrogen, look at the mass numbers from the equation. What do they have to equal?

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1masses, not atomic numbers

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1so the whole equation will look like: \[\large{^{14}_{6}C \rightarrow \space ^{0}_{1} \beta + \space ^{A}_{7}N}\]

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1\[\large{^{14}_{6}C \rightarrow \space ^{0}_{1} \beta + \space ^{14}_{7}N}\]

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1so now that you have a completed beta decay equation, you can answer the question

JFraser
 one year ago
Best ResponseYou've already chosen the best response.1the atomic number goes from 6 to 7, so it must increase by one
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