## superhelp101 one year ago Question:

1. superhelp101

When an atom releases a beta particle, the mass number decreases by one. the mass number increases by one. the atomic number increases by one. the atomic number remains the same.

2. superhelp101

@JFraser

3. JFraser

what is the isotopic symbol for a beta particle?

4. superhelp101

|dw:1438469062312:dw|

5. superhelp101

isn't it?

6. JFraser

that's the one

7. JFraser

now suppose an atom of carbon-14 undergoes beta decay

8. JFraser

$^{14}_{6}C \rightarrow ^0_{-1} \beta + ^A_Z?$

9. JFraser

in nuclear reactions, the $$total$$ atomic number must be conserved, and the $$total$$ mass number must also be conserved

10. superhelp101

oh okay

11. JFraser

since the total atomic number $$must$$ add up to 6, what must the other particle be to make the bottom "equation" true?

12. superhelp101

7?

13. JFraser

since those are atomic numbers, what particle has an atomic number of 7?

14. superhelp101

nitrogen

15. JFraser

and what about the mass number?

16. superhelp101

nitrogen atomic mass 14.00674

17. superhelp101

litium

18. JFraser

you don't need the average mass of nitrogen, look at the mass numbers from the equation. What do they have to equal?

19. superhelp101

6

20. JFraser

masses, not atomic numbers

21. superhelp101

14

22. JFraser

very good

23. JFraser

so the whole equation will look like: $\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{A}_{7}N}$

24. superhelp101

yes

25. JFraser

$\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{14}_{7}N}$

26. JFraser

so now that you have a completed beta decay equation, you can answer the question

27. superhelp101

C?

28. JFraser

the atomic number goes from 6 to 7, so it must increase by one

29. JFraser

good job

30. superhelp101

thx