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superhelp101

  • one year ago

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  1. superhelp101
    • one year ago
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    When an atom releases a beta particle, the mass number decreases by one. the mass number increases by one. the atomic number increases by one. the atomic number remains the same.

  2. superhelp101
    • one year ago
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    @JFraser

  3. JFraser
    • one year ago
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    what is the isotopic symbol for a beta particle?

  4. superhelp101
    • one year ago
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    |dw:1438469062312:dw|

  5. superhelp101
    • one year ago
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    isn't it?

  6. JFraser
    • one year ago
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    that's the one

  7. JFraser
    • one year ago
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    now suppose an atom of carbon-14 undergoes beta decay

  8. JFraser
    • one year ago
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    \[^{14}_{6}C \rightarrow ^0_{-1} \beta + ^A_Z?\]

  9. JFraser
    • one year ago
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    in nuclear reactions, the \(total\) atomic number must be conserved, and the \(total\) mass number must also be conserved

  10. superhelp101
    • one year ago
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    oh okay

  11. JFraser
    • one year ago
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    since the total atomic number \(must\) add up to 6, what must the other particle be to make the bottom "equation" true?

  12. superhelp101
    • one year ago
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    7?

  13. JFraser
    • one year ago
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    since those are atomic numbers, what particle has an atomic number of 7?

  14. superhelp101
    • one year ago
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    nitrogen

  15. JFraser
    • one year ago
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    and what about the mass number?

  16. superhelp101
    • one year ago
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    nitrogen atomic mass 14.00674

  17. superhelp101
    • one year ago
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    litium

  18. JFraser
    • one year ago
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    you don't need the average mass of nitrogen, look at the mass numbers from the equation. What do they have to equal?

  19. superhelp101
    • one year ago
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    6

  20. JFraser
    • one year ago
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    masses, not atomic numbers

  21. superhelp101
    • one year ago
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    14

  22. JFraser
    • one year ago
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    very good

  23. JFraser
    • one year ago
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    so the whole equation will look like: \[\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{A}_{7}N}\]

  24. superhelp101
    • one year ago
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    yes

  25. JFraser
    • one year ago
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    \[\large{^{14}_{6}C \rightarrow \space ^{0}_{-1} \beta + \space ^{14}_{7}N}\]

  26. JFraser
    • one year ago
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    so now that you have a completed beta decay equation, you can answer the question

  27. superhelp101
    • one year ago
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    C?

  28. JFraser
    • one year ago
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    the atomic number goes from 6 to 7, so it must increase by one

  29. JFraser
    • one year ago
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    good job

  30. superhelp101
    • one year ago
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    thx

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