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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \begin{cases} {\color{brown}{ y}}=x^2+36\\ {\color{brown}{ y}}=2x+21 \end{cases}\qquad well\qquad \begin{array}{cccllll} {\color{brown}{ y}}&=&{\color{brown}{ y}} \\ \quad \\ x^2+36&=&2x+21 \end{array}\qquad thus \\ \quad \\ x^2+36=2x+21\implies 36=x^2+2x+21 \\ \quad \\ 0=x^2+2x+2136\implies0=x^2+2x15\qquad \\ \quad \\ notice\qquad \begin{array}{cccllll} x^2&+2x&15\\ &\uparrow &\uparrow \\ &53&5\cdot 3 \end{array} \\ \quad \\ 0=(x+5)(x3)\) solve for "x" once you found "x", get "y" by substitution
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