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anonymous
 one year ago
A 6.0 cm object is located 20 cm in front of
a convex mirror with a radius of curvature
equal to 120 cm. What is the size
of the image produced by the mirror?
anonymous
 one year ago
A 6.0 cm object is located 20 cm in front of a convex mirror with a radius of curvature equal to 120 cm. What is the size of the image produced by the mirror?

This Question is Closed

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3how did you do it? you first....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k i found 1.5 for di

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in the end it did (1.5)(6)/20

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3what is f in this question??!!

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3seems we are in agreement  ish (___), cool. for me: \(\large \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\) \(f = 60\) \(d_o = 20 \implies d_i = 15\) \( \large \frac{h_i}{h_0} = \frac{d_i}{d_o} \) \(h_o = 6\) follows that \(h_i = 4.5\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.31/60 = 1/20 +1/di

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea so when the 1/20 come to the other side it becomes negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh wait its 1200 not 120

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these question are really easy just these silly mistakes ruin them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw do u come to site often ? i will be needing lots of help in the coming days since i have excam

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\) \(f =  60\) \(\large \frac{1}{60} = \frac{1}{20} + \frac{1}{d_i}\) \(\large \frac{1}{d_i} = \frac{1}{60}  \frac{1}{20} = \frac{1}{20} (\frac{1}{3} + 1) = \frac{1}{15}\) \(\large d_i = 15\) \(\large \frac{h_i}{h_o} = \frac{d_i}{d_o}\) etc etc

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3plus, for "lots of help" on Physics, be sure to tag @Michele_Laino Qualified Helper, and brilliant in every sense of the word

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0thanks!! @IrishBoy123
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