anonymous
  • anonymous
A 6.0 cm object is located 20 cm in front of a convex mirror with a radius of curvature equal to 120 cm. What is the size of the image produced by the mirror?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@IrishBoy123
anonymous
  • anonymous
i get 0.45 and u ?
anonymous
  • anonymous
@IrishBoy123

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More answers

IrishBoy123
  • IrishBoy123
4.5
anonymous
  • anonymous
how did u do it?
IrishBoy123
  • IrishBoy123
how did you do it? you first....
anonymous
  • anonymous
k i found -1.5 for di
anonymous
  • anonymous
in the end it did (1.5)(6)/20
anonymous
  • anonymous
to get 0.45
IrishBoy123
  • IrishBoy123
what is f in this question??!!
IrishBoy123
  • IrishBoy123
\(R_c = 120\)
IrishBoy123
  • IrishBoy123
so f = ??
anonymous
  • anonymous
60
anonymous
  • anonymous
-60 since it convex
IrishBoy123
  • IrishBoy123
seems we are in agreement - ish (___), cool. for me: \(\large \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\) \(f = -60\) \(d_o = 20 \implies d_i = -15\) \( \large \frac{h_i}{h_0} = -\frac{d_i}{d_o} \) \(h_o = 6\) follows that \(h_i = 4.5\)
anonymous
  • anonymous
-1/60-1/20=1/di???
anonymous
  • anonymous
@IrishBoy123
IrishBoy123
  • IrishBoy123
-1/60 = 1/20 +1/di
anonymous
  • anonymous
yea so when the 1/20 come to the other side it becomes negative
anonymous
  • anonymous
ohh wait its 1200 not 120
anonymous
  • anonymous
omg
anonymous
  • anonymous
these question are really easy just these silly mistakes ruin them
anonymous
  • anonymous
btw do u come to site often ? i will be needing lots of help in the coming days since i have excam
IrishBoy123
  • IrishBoy123
\(\large \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\) \(f = - 60\) \(\large -\frac{1}{60} = \frac{1}{20} + \frac{1}{d_i}\) \(\large \frac{1}{d_i} = -\frac{1}{60} - \frac{1}{20} = -\frac{1}{20} (\frac{1}{3} + 1) = -\frac{1}{15}\) \(\large d_i = -15\) \(\large \frac{h_i}{h_o} = -\frac{d_i}{d_o}\) etc etc
IrishBoy123
  • IrishBoy123
plus, for "lots of help" on Physics, be sure to tag @Michele_Laino Qualified Helper, and brilliant in every sense of the word
Michele_Laino
  • Michele_Laino
thanks!! @IrishBoy123

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