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The inscribed angle = 1/2(the intercepted arc)

For the second one I have no idea what QR and LN represent so can't help with that one.

For #2, if they are congruent, then it means they are equal.

\[\huge QR≅LN\]\[\huge 5x=3x+54\]

Once you solve for x, plug that number in the x of QR.

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You shouldn't add 3x. You should subtract it. :)

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thank you my X was 27 and then I did 5(27) and that gave me 135 thank you :)

Yes that's right. @Juicy1116 :)

I also wanted to know is the first problem similar to this way I worked it out

Can you show your work?

Like what Mertsj said, the formula is the inscribed angle = 1/2(the intercepted arc).

Or if you don't want to deal with fractions,\[2\times m∠C=arc AB\]

l|dw:1438476983732:dw|

Hmm do you mean like this I'm kinda lost :(

You flipped the arc and the angle.

What is the measure of angle C?

\[\huge 2\times m∠C=arc AB\]\[\huge 2(3x+5)=16x\]

I hope you can find the x now.

Did you get it?

Not quite but I got 5 so I think that's right

Do you know how to distribute 3 to 3x+5? What class are you taking?

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