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The inscribed angle = 1/2(the intercepted arc)
For the second one I have no idea what QR and LN represent so can't help with that one.
@Mertsj thanks but I still don't get it
For #2, if they are congruent, then it means they are equal.
\[\huge QR≅LN\]\[\huge 5x=3x+54\]
Once you solve for x, plug that number in the x of QR.
@mathway okay I tried to plug it in this is how I did it
You shouldn't add 3x. You should subtract it. :)
thank you my X was 27 and then I did 5(27) and that gave me 135 thank you :)
Yes that's right. @Juicy1116 :)
I also wanted to know is the first problem similar to this way I worked it out
Can you show your work?
Like what Mertsj said, the formula is the inscribed angle = 1/2(the intercepted arc).
Or if you don't want to deal with fractions,\[2\times m∠C=arc AB\]
Hmm do you mean like this I'm kinda lost :(
You flipped the arc and the angle.
What is the measure of angle C?
\[\huge 2\times m∠C=arc AB\]\[\huge 2(3x+5)=16x\]
I hope you can find the x now.
Did you get it?
Not quite but I got 5 so I think that's right
Do you know how to distribute 3 to 3x+5? What class are you taking?
@mathway I'm trying to. Can you explain please