anonymous
  • anonymous
Find the value of x and y in the diagram below. (okay so I attempted this problem, but I still did not get the correct answer)
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
rishavraj
  • rishavraj
its a rectangle for sure..... do u know to get projections???
anonymous
  • anonymous
I don't even know what that means :o @rishavraj

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
What did you do? It's similar to what we did earlier. :)
anonymous
  • anonymous
I did 9(x)= 9 sqrt 2
anonymous
  • anonymous
|dw:1438480912945:dw|
anonymous
  • anonymous
So 9 is the \[a \sqrt{3}\] because it is the opposite of 60 degrees.
anonymous
  • anonymous
So I do 9 sqrt 3?
anonymous
  • anonymous
No. Because 9 is not the a. You need to find the a first.
anonymous
  • anonymous
So you must equal 9 to a square root of 3.
anonymous
  • anonymous
\[\huge 9=a \sqrt{3}\]
anonymous
  • anonymous
Now solve for a.
anonymous
  • anonymous
Oh brothers.. how do I solve for a if it's not a legit numbers? unless 2 is a..
anonymous
  • anonymous
|dw:1438481307802:dw|
anonymous
  • anonymous
ohhh I think I might get it. So y must equal 4.5
anonymous
  • anonymous
Hmmm idk what you're talking about. :D
anonymous
  • anonymous
So a= 9/sq rt of 3 but you still need to rationalize it. You can't have a square root in the denominator.
anonymous
  • anonymous
|dw:1438481444679:dw|
anonymous
  • anonymous
You think you can simplify \[\frac{ 9\sqrt{3} }{ 3 }\]
anonymous
  • anonymous
|dw:1438481621511:dw|
anonymous
  • anonymous
|dw:1438481661467:dw|
anonymous
  • anonymous
After that, you will find 2a or x in your problem. \[3\sqrt{3}\times2=?\]
anonymous
  • anonymous
ohh so I got 6.92820323028
anonymous
  • anonymous
Oh you don't have to find the exact value. Look at your choices.
anonymous
  • anonymous
To multiply this, what is 3 times 2? Then simply put the square root of 3.
triciaal
  • triciaal
|dw:1438481623939:dw|
anonymous
  • anonymous
|dw:1438481942163:dw|
anonymous
  • anonymous
I got 10.3923048454
anonymous
  • anonymous
|dw:1438482010381:dw|
anonymous
  • anonymous
What is 3 times 2?
anonymous
  • anonymous
6
anonymous
  • anonymous
Then add the square root of 3. Then that's it.
anonymous
  • anonymous
|dw:1438482119315:dw|
anonymous
  • anonymous
I give up it's all coming out in decimals :o
anonymous
  • anonymous
That is simply 6 sq root of 3. You don't have to use the calculator.
anonymous
  • anonymous
|dw:1438482340382:dw|
triciaal
  • triciaal
|dw:1438482460151:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.