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@nincompoop please cheque my work....:)
does my work make any sense to you????????o_O
that's such a political response but i'll take that as a yes!!!
Thank you :)
I think nincompoop's profile picture matches your question and it's tilting it's head to read what you wrote :P
@IrishBoy123 please help
i;ve already done the question but the answer is different
what have i done wrong??????
well the car is deaccelerating so u need to take the acceleration as -2.3m/s^2 :)
ok let me try the question that way and i;ll get back to you
try to think this way - if the car ws accelerating instead of deaccelerating then it wuld have certainly covered more distance. so if u try to calculate the distance covered by the accelerating car u wuld apply this formula- S=ut +1/2 at^2 but u r applying the same formula for deaccelrating car so u r getting the same distance nd this is not possible so u can conclude that u made a mistake while taking the sign of acceleration :)
got it......i got the answer Thanks man :)
@Astrophysics LOL my question was pretty easy, maybe she has a sprained neck or something.
Haha, yes, kinematics problems aren't too difficult, the problem most people have with this is, the terms, and knowing what they mean. it can get confusing I guess, when you're dealing with average velocity, instantaneous velocity, displacement, distance, deceleration, etc =P
So for now you can think of deceleration as negative acceleration
deceleration = - a
got it...actually i've this this unit before but yah i guess i forgot about this particular thing LOL :D
Haha, yeah but if you want to be technical, deceleration really just means decrease in speed, I really don't like this term though xD.
me neither....!!! XD