anonymous
  • anonymous
ΔABC with vertices A(-3, 0), B(-2, 3), C(-1, 1) is rotated 180° clockwise about the origin. It is then reflected across the line y = -x. What are the coordinates of the vertices of the image?
Geometry
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anonymous
  • anonymous
ΔABC with vertices A(-3, 0), B(-2, 3), C(-1, 1) is rotated 180° clockwise about the origin. It is then reflected across the line y = -x. What are the coordinates of the vertices of the image?
Geometry
katieb
  • katieb
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taramgrant0543664
  • taramgrant0543664
|dw:1438492100436:dw| So this is a kind of bad attempt on drawing the initial triangle, so you have to determine which point is your point of origin first so that we can rotate it 180 degrees
taramgrant0543664
  • taramgrant0543664
The origin is where the two axis meet so right as (0,0) so we will have to rotate the triangle 180 degrees round that point
taramgrant0543664
  • taramgrant0543664
|dw:1438492499423:dw| Do you have a guess on what those coordinates are for the new triangle?

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taramgrant0543664
  • taramgrant0543664
A is at (3,0) instead of (-3,0) B is at (2,-3) instead of (-2,30 C is at (1,-1) instead of (-1,1)
taramgrant0543664
  • taramgrant0543664
After that you will want to reflect it across the line y=-x to determine your final triangle
taramgrant0543664
  • taramgrant0543664
You're final triangle will have the points A(0,-3) B(-3,2) C(-1,1) I'm pretty sure it should be these points
anonymous
  • anonymous
yes as taramgrant said .. going by similar procedure we will have the points of the reflected traingle(shown as dashed)|dw:1438493029033:dw|
taramgrant0543664
  • taramgrant0543664
Just realized that my B point for the reflection was wrong I just put the negatives in the wrong place B should be (3,-2) Nick's drawing is right there if you want to do it all together or you can do each step individually depending on what's best for you

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