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anonymous

  • one year ago

Which statement is true about the product square root of 2(3square root of 2 + square root of 18)? It is rational and equal to 12. It is rational and equal to 18. It is irrational and equal to 6 + 2square root of 18. It is irrational and equal to 3 +square root of 18.

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  1. anonymous
    • one year ago
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    |dw:1438492756331:dw|

  2. anonymous
    • one year ago
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    It looks like that

  3. anonymous
    • one year ago
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    \[\sqrt{2}(\sqrt{2}\times3+\sqrt{18})=\sqrt{2}(\sqrt{2}\times3+\sqrt{2}\sqrt{9})\] \[\sqrt{2}(\sqrt{2}\times3+\sqrt{2}\times3)=\sqrt{2}(\sqrt{2}\times6)\]

  4. anonymous
    • one year ago
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    \[\sqrt{2}\times \sqrt{2} \times 6=2 \times 6\]

  5. anonymous
    • one year ago
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    you got the idea?

  6. anonymous
    • one year ago
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    So you don't distribute the √2 ?

  7. anonymous
    • one year ago
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    no not until you deal with the sqrt18

  8. anonymous
    • one year ago
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    sqrt to outside can wait

  9. anonymous
    • one year ago
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    Oh wow thank you so much! fan and medal for you

  10. anonymous
    • one year ago
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    I have one more will you help me?

  11. anonymous
    • one year ago
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    12 is answer

  12. anonymous
    • one year ago
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    ok

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spraguer (Moderator)
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