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anonymous

  • one year ago

Simplify 3√5 - 2√7 + √45 -√28. 2√12 2√2 6√5 - 4√7 6√10 - 4√14

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  1. UnkleRhaukus
    • one year ago
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    what are prime factors of 45?

  2. anonymous
    • one year ago
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    5 , 15, 3

  3. UnkleRhaukus
    • one year ago
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    15 is not prime

  4. anonymous
    • one year ago
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    5?

  5. anonymous
    • one year ago
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    ok i gt ya

  6. UnkleRhaukus
    • one year ago
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    45 = 3 * 3 * 5 right?

  7. anonymous
    • one year ago
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    yes

  8. UnkleRhaukus
    • one year ago
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    you have one term that is √45 √45 = √(3 * 3 * 5) = √(3^2 * 5) = √3^2 * √5 = 3 * √5

  9. UnkleRhaukus
    • one year ago
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    because √x^2 = x and √(x * y) = √x * √y

  10. UnkleRhaukus
    • one year ago
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    do you know the prime factorization of 28?

  11. anonymous
    • one year ago
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    \[3\sqrt{5}-2\sqrt{7}+3\sqrt{5}+\sqrt{9}\sqrt{5}-2\sqrt{7}\]\[3\sqrt{5}+3\sqrt{5}-2\sqrt{7}-2\sqrt{7}\]\[6\sqrt{5}-4\sqrt{7}\]

  12. anonymous
    • one year ago
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    |dw:1438494763109:dw|

  13. anonymous
    • one year ago
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    dayum you draw better than me

  14. anonymous
    • one year ago
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    haha...took me long enough...

  15. anonymous
    • one year ago
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    i tried to show draw the steps to find 3x3 determinant and it went out of screen yesterday

  16. anonymous
    • one year ago
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    i tried answering a question yesterday but dont know if my approach was right..would u mind checking that out.. though the question is already closed..

  17. anonymous
    • one year ago
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    sure send me da link

  18. anonymous
    • one year ago
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    oh wow thank

  19. anonymous
    • one year ago
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    i didn't see that

  20. anonymous
    • one year ago
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    http://openstudy.com/updates/55bcdad5e4b0a2b3ffc5d26f

  21. anonymous
    • one year ago
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    |dw:1438495588987:dw| i don't understand how the circle part is the answer

  22. anonymous
    • one year ago
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    3*3*5 ??? how does that turn into that

  23. anonymous
    • one year ago
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    nick, i would go with welsh drawing lol yours looks kinda complicated. \[45=3*3*5\]\[\sqrt{45}=\sqrt{9}\sqrt{5}=3\sqrt{5}\]

  24. anonymous
    • one year ago
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    OH. WOW THANK YOU

  25. anonymous
    • one year ago
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    |dw:1438495869837:dw|

  26. anonymous
    • one year ago
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    @saseal thanks anyways for looking...

  27. anonymous
    • one year ago
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    i used to look at it this way \[\sqrt{2}=2^{\frac{ 1 }{ 2 }}\]

  28. anonymous
    • one year ago
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    yw

  29. anonymous
    • one year ago
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    |dw:1438496337543:dw|

  30. anonymous
    • one year ago
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    oh. ok thank you

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