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anonymous

  • one year ago

H.E.L.P check attachment please!

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  1. anonymous
    • one year ago
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  2. arindameducationusc
    • one year ago
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    Where is function1?

  3. arindameducationusc
    • one year ago
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    Oh I saw wait....

  4. arindameducationusc
    • one year ago
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    What do you think?

  5. anonymous
    • one year ago
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    @arindameducationusc i honestly have no clue. I'm hoping one of you guys cold teach me how to do this

  6. ganeshie8
    • one year ago
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    |dw:1438518500301:dw|

  7. ganeshie8
    • one year ago
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    see if you can eyeball the "y" coordinate of that point from the graph

  8. anonymous
    • one year ago
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    @ganeshie8 0

  9. ganeshie8
    • one year ago
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    That is a good try, but no. 0 is the x coordinate of that point, not y coordinate

  10. ganeshie8
    • one year ago
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    try again

  11. anonymous
    • one year ago
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    oh 3

  12. ganeshie8
    • one year ago
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    Yes! so 3 is the maximum value of function 2 lets try and see if function1 can take values greater than this

  13. ganeshie8
    • one year ago
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    |dw:1438519360039:dw|

  14. ganeshie8
    • one year ago
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    \(f(0) = -4*0^2+6*0+3 = 3\) Looks like the first function takes values greater than 3 ?

  15. anonymous
    • one year ago
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    so the first function would be the answer?

  16. ganeshie8
    • one year ago
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    Yes we can conclude that the maximum value of first function has to be at least 3. It turns out first function is the answer

  17. anonymous
    • one year ago
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    thank you!! @ganeshie8

  18. ganeshie8
    • one year ago
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    np If you graph the first function, it is easy to see that the maximum value is greater than 3 : |dw:1438519680410:dw|

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is replying to Can someone tell me what button the professor is hitting...

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