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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0split the middle term, do you know how to do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0kind of but could you please walk me through the steps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll try when you split the middle term of a quadratic polynomial \[p(x)=ax^2+bx+c\] you are looking to split b into two numbers say, f and g such that \[b=f+g\] and \[f \times g =a \times c\] Do you understand this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok now calculate \[a \times c\] for the polynomial u r given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438524585865:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay keep going i understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u find the product of a and c for me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok good, now what is your b?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0great, now can you think of two numbers u can split b(that is 4 in this case) into, such that the product of those numbers will equal 12 and adding those numbers will give u back 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0good job!! now just split b and work it out as \[12x^2+(6+2)x1=12x^26x+2x1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factorize first 2 terms together and last 2 terms together

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438524844892:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0take out as much factors out as u can from the first 2 terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438524921185:dw What does that say?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's 6x, for the first 2 terms what can u take out??what is common in 12x^2 and 6x ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0good, now so now we have \[6x(2x1)+(2x1)\] Now we have two terms, you can take 2x1 out, what are you left with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nope, you are missing something!! \[(2x1)(6x+??)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep! and there you have your factors, nice and clean \[(2x1)(6x+1)\] Just to verify, let's open these up \[(2x \times 6x)+( 1 \times 6x)+(2x \times 1)+(1 \times 1)=12x^26x+2x1=12x^24x1\]
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