## -Welp- one year ago How do I solve this?

1. -Welp-

|dw:1438527061044:dw| "find the area of the triangle"

2. Rushwr

is that all ? No anyother angles given >

3. -Welp-

That's all they gave me to work with

4. Rushwr

have they atleast mentioned about the left over angles being same or something?

5. -Welp-

|dw:1438527348097:dw| I got it backwards

6. -Welp-

*Sorry, I had it backwards

7. Rushwr

Soo do u want to know the whole procedure or just how to take the angles. !

8. -Welp-

The whole procedure please

9. anonymous

You use cosine rule for this right?

10. Rushwr

That's what I was thinking too ! NOt sure though ! Still thinking ! WOuld you mind helping us @paki

11. anonymous

$a^2=b^2+c^2-2bc \cos A$

12. anonymous

$a=\sqrt{12^2+8^2-2(12(8)\cos 81}$

13. anonymous

lets see what you get

14. -Welp-

I got 13.34033668 that doesn't seem right

15. anonymous

you can verify it with sine rule now that you have 3 sides

16. amistre64

how would you usually figure out the are of a triangle?

17. amistre64

|dw:1438530093183:dw|

18. amistre64

how would we determine the height? do we know any trig functions that we could employ?

19. triciaal

another approach after using the cosine rule to get the 3rd side use Hero's formula to find the area knowing the 3 sides

20. triciaal

|dw:1438531174056:dw|

21. -Welp-

"you can verify it with sine rule now that you have 3 sides" Formula for sine rule? "how would we determine the height? do we know any trig functions that we could employ?" I don't know "another approach after using the cosine rule to get the 3rd side use Hero's formula to find the area knowing the 3 sides " I don't know what I did wrong but I got 177

22. zepdrix

Formula for Sine Rule:$\large\rm \frac{a}{\sin A}=\frac{b}{\sin B}$|dw:1438535217539:dw|

23. zepdrix

Ya I like that Law of Cosines approach :o

24. -Welp-

=47.4 ^Is that correct?