In attempting to synthesize cyclohexane from benzene, they somehow got methylcyclopentane. Can anyone write out probable steps going from benzene to methylcyclopentane with HI at 275 degrees C?
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This should be reaction of rearrangement.
In the first place, you add H+, and you for a carbo cataion, and as the structure now is instable, when you rise up the T, it shoud break and rearrange in more stable way.
But HI works also ad a reducent agent 2HI--> I2 + H2, where H2 will also make weaker all the structure. So that's why u cant use another acid as HBr or HCl, cuz of their redox potential.
Oh, so does that mean HI has a high redox potential and HBr and HCl have a low redox potential?
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Try to think about the eletconegativity: for Clorine use to riduce a lot, Br little bit less, and I has pretty low tendence to reduce, so it easyer for I to get reoxidated, while i think you will be in touble if you will try to reoxidate Cl- in Cl2
I would like to see the mechanism for this step by step.