anonymous
  • anonymous
1.) The area of a regular octagon is 35 cm squared. What is the area of a regular octagon with sides three times as long? My answer: 315 cm squared. Is that correct? 2.) Name the minor arc and find its measure. http://assets.openstudy.com/updates/attachments/4fb5f543e4b05565342bcb5a-kamuela710-1337324879047-4568453162011122648pm17916 My answer: ADB has a measure of 245. Is that correct?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
3.) The figures below are similar. What are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? The figures are not drawn to scale. http://assets.openstudy.com/updates/attachments/55bcef17e4b0c4d93d6c2874-lollygirl217-1438476949164-as.jpg My answer: 13/3=169/9. Is that correct?
anonymous
  • anonymous
anonymous
  • anonymous

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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
amistre64
  • amistre64
how do we determine the area of a regular octagon to start with?
amistre64
  • amistre64
im pretty sure the general solution is that a change in linear measures, scale by ^2 in area
amistre64
  • amistre64
so 315 sounds good to me, but i always have to dbl chk with the brute method since i cant recall thrms that well
anonymous
  • anonymous
Alright, do your thing.
amistre64
  • amistre64
a triangle ... base s, apothem a, area = sa/2 and there is 8 of them area = 4 sa linear measures factor by 3 so: 4(3s)(3a) = 3^2 (4sa) in this case 3^2 (35) is good
amistre64
  • amistre64
the link to the arc is bad
anonymous
  • anonymous
Oh it is? Hold on.
anonymous
  • anonymous
1 Attachment
amistre64
  • amistre64
ok, and what does it mean to be a minor arc?
anonymous
  • anonymous
@amistre64 well firsts things first. Did I get any of them right?
anonymous
  • anonymous
I mean that one right.
amistre64
  • amistre64
yes, i verified that 315 is correct. on the second one, and the third one, i would perfer to see how you came to your solutions first tho.
amistre64
  • amistre64
to determine the solution to number 2, we need to agree on the definition of a minor arc.
anonymous
  • anonymous
Perhaps it's just AB has a measure of 245.
anonymous
  • anonymous
AB is minor because of the two arcs in the circle AB has a measure of 115 degrees and ADB has a measure of 245. This is what I say
amistre64
  • amistre64
perhaps, but that depends on what our definition of a minor arc is ...
amistre64
  • amistre64
AB is minor, agreed, since it is less then 180 .. and it is measured for us already as 115
amistre64
  • amistre64
we good to move on to #3?
anonymous
  • anonymous
So then it would be ab measured as 115?
amistre64
  • amistre64
correct
anonymous
  • anonymous
Lol...how did I make that mistake?
amistre64
  • amistre64
:) pretty sure you read minor as "major" ... i read things too fast sometimes as well
anonymous
  • anonymous
Yeah, I did.
amistre64
  • amistre64
tell me how you approached #3
anonymous
  • anonymous
a) ratio of perimeters = 26/6 = 13/3 b) ratio of areas = (13/3)² = 169/9 <----------A = L²
amistre64
  • amistre64
i like it.
amistre64
  • amistre64
not sure if the notation is correct, since im not taking your class specifically 13:3, or 1 : 13/3 is what i am used to playing with
amistre64
  • amistre64
if the ratio of sides of similar shapes is: 1:k the ratio of their ares is: 1:k^2
anonymous
  • anonymous
So it is 13/3, I got have of it right. Then it must be 13/3 and 16/9
anonymous
  • anonymous
Or are you saying I got it right??
amistre64
  • amistre64
you got it right; 13/3 and 13^2/3^2 is fine
amistre64
  • amistre64
13^2 = 169 3^2 = 9 just make sure your notation is accurate to your course.
amistre64
  • amistre64
going from large to small might mean: 3/13 and 9/169
anonymous
  • anonymous
Alright thank you.

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