- anonymous

1.) The area of a regular octagon is 35 cm squared. What is the area of a regular octagon with sides three times as long?
My answer: 315 cm squared. Is that correct?
2.) Name the minor arc and find its measure.
http://assets.openstudy.com/updates/attachments/4fb5f543e4b05565342bcb5a-kamuela710-1337324879047-4568453162011122648pm17916
My answer: ADB has a measure of 245. Is that correct?

- katieb

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- anonymous

3.) The figures below are similar. What are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? The figures are not drawn to scale.
http://assets.openstudy.com/updates/attachments/55bcef17e4b0c4d93d6c2874-lollygirl217-1438476949164-as.jpg
My answer: 13/3=169/9. Is that correct?

- anonymous

- anonymous

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## More answers

- anonymous

- anonymous

- anonymous

- amistre64

how do we determine the area of a regular octagon to start with?

- amistre64

im pretty sure the general solution is that a change in linear measures, scale by ^2 in area

- amistre64

so 315 sounds good to me, but i always have to dbl chk with the brute method since i cant recall thrms that well

- anonymous

Alright, do your thing.

- amistre64

a triangle ... base s, apothem a, area = sa/2 and there is 8 of them
area = 4 sa
linear measures factor by 3 so: 4(3s)(3a) = 3^2 (4sa)
in this case 3^2 (35) is good

- amistre64

the link to the arc is bad

- anonymous

Oh it is? Hold on.

- anonymous

##### 1 Attachment

- amistre64

ok, and what does it mean to be a minor arc?

- anonymous

@amistre64 well firsts things first. Did I get any of them right?

- anonymous

I mean that one right.

- amistre64

yes, i verified that 315 is correct.
on the second one, and the third one, i would perfer to see how you came to your solutions first tho.

- amistre64

to determine the solution to number 2, we need to agree on the definition of a minor arc.

- anonymous

Perhaps it's just AB has a measure of 245.

- anonymous

AB is minor because of the two arcs in the circle AB has a measure of 115 degrees and ADB has a measure of 245. This is what I say

- amistre64

perhaps, but that depends on what our definition of a minor arc is ...

- amistre64

AB is minor, agreed, since it is less then 180 .. and it is measured for us already as 115

- amistre64

we good to move on to #3?

- anonymous

So then it would be ab measured as 115?

- amistre64

correct

- anonymous

Lol...how did I make that mistake?

- amistre64

:) pretty sure you read minor as "major" ... i read things too fast sometimes as well

- anonymous

Yeah, I did.

- amistre64

tell me how you approached #3

- anonymous

a) ratio of perimeters = 26/6 = 13/3
b) ratio of areas = (13/3)² = 169/9 <----------A = L²

- amistre64

i like it.

- amistre64

not sure if the notation is correct, since im not taking your class specifically
13:3, or 1 : 13/3 is what i am used to playing with

- amistre64

if the ratio of sides of similar shapes is: 1:k
the ratio of their ares is: 1:k^2

- anonymous

So it is 13/3, I got have of it right. Then it must be 13/3 and 16/9

- anonymous

Or are you saying I got it right??

- amistre64

you got it right; 13/3 and 13^2/3^2 is fine

- amistre64

13^2 = 169
3^2 = 9
just make sure your notation is accurate to your course.

- amistre64

going from large to small might mean:
3/13 and 9/169

- anonymous

Alright thank you.

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