anonymous
  • anonymous
A student says that if P(A) = P(A|B), then A and B must be independent events. Is the student correct? Explain. Give a real life example that can be represented by P(A) = P(A|B).
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
what is your definition of independence?
anonymous
  • anonymous
One event doesn't depend on the other?
amistre64
  • amistre64
thats a little vague, how does it differ from mutually exclusive events?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Mutually exclusive events cannot happen at the same time, but independent events can happen at the same time
anonymous
  • anonymous
It's just that the probability of one event happening in no way affects the other happening
amistre64
  • amistre64
correct so if the probability of an event happening, is the same for all cases ... then the probability of the event is independent of the circumstances spose there are 3 As that occur in a total of 5 Bs. P(A|B) read as, the probability of A given B, is 3/5 spose there are 6 As out of a universal set of 10 P(A|U), or simply P(A) , is 6/10 = 3/5 the probability of A is independent of the case it is a part of.
amistre64
  • amistre64
if P(A) = P(A|B) = P(A|C) = P(A|D) = ... = P(A|K) then the probability of A is the same, for all given cases, and its value does not depend on any one specific case.
anonymous
  • anonymous
okay, that makes sense, thank you
amistre64
  • amistre64
good luck :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.