A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

AmTran_Bus

  • one year ago

Find an equation of the tangent to the curve at the point by first eliminating the parameter

  • This Question is Closed
  1. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x=e^t , y=(t-6)^2 ; (1,36)

  2. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I tried to elem. the parameter and got lnx^2 - 12lnx +36 ?

  3. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    why would we want to eliminate the parameter? just because it says so?

  4. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Correct.

  5. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Did I even do it right?

  6. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ln(x) = t is suitable sure

  7. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hum. So what do I do to get the equation? I cant just plug in (1,36) for x and y because ln(1) is 0.

  8. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    well, since y = (t-6)^2, and t=ln(x) y = (ln(x)-6)^2

  9. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    in order to make a line, we need a point and a slope ... how do we find the slope?

  10. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    or lnx^2-12lnx+36

  11. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no need to expand it ..

  12. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hum. Ok. So y-y1=m(x-x1)

  13. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    good, and we have y1 and x2, we only need m

  14. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    typos lol

  15. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So just take delta y/delta x? Which is ... um...

  16. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    which is chain rule ...

  17. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh. Duh. Gotta take deriv. of that.

  18. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yep

  19. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Give me a sec!

  20. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2(lnx-6)*1/x

  21. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    very good, and when x=1? m=?

  22. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -6?

  23. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    2(0-6)/1 is not -6

  24. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It is if you are lazy and plug it in your calc wrong. :)

  25. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    lol

  26. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -12

  27. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so whats our line?

  28. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=-12x+

  29. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    gott get that last number.

  30. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    y-36 = -12(x-1) is the equation of a line ... but format however you want

  31. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okie dokie. So just -12x+1+36? So y=-12x+37?

  32. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -12x -12(-1) +36 so no

  33. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Story of my life. How about -12x+12+36 or y=-12x+48

  34. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    looking good lol

  35. AmTran_Bus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So algebra is harder than calculus. Thank you.

  36. amistre64
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i agree :)

  37. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.