anonymous
  • anonymous
Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extraneous or not. x = 4, extraneous x = 4, non-extraneous x = -4, extraneous x = -4, non-extraneous
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\frac{4}{x-4}=\frac{x}{x-4}-\frac{4}{3}\]?
anonymous
  • anonymous
yes
anonymous
  • anonymous
there is no solution, so not sure why you are supposed to come up with one

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More answers

anonymous
  • anonymous
i guess since there is no solution you are supposed to say x = 4, extraneous
anonymous
  • anonymous
if you subtract you get \[\frac{4-x}{x-4}=-\frac{4}{3}\]
anonymous
  • anonymous
since \(\frac{4-x}{x-4}=-1\) you have \[-1=-\frac{4}{3}\] which is silly
anonymous
  • anonymous
not sure why you are supposed to say "4, extraneous" when "no solution" should suffice, but what do i know? must be some math teacher way to solve that gives \(4\) as an answer, even though it isn't one
anonymous
  • anonymous
im not understanding
anonymous
  • anonymous
subtract \(\frac{x}{x-4}\) from both sides of the equation
phi
  • phi
how do people come up with these questions??!
anonymous
  • anonymous
you get \[\frac{4-x}{x-4}=-\frac{3}{4}\]
anonymous
  • anonymous
the left hand side is a number, it is \(-1\)
anonymous
  • anonymous
the answer choices are under the question
anonymous
  • anonymous
@phi no clue
anonymous
  • anonymous
go with x = 4, extraneous
anonymous
  • anonymous
extraneous is math teacherese for "no solution"
anonymous
  • anonymous
ok ill let you know if its right or wrong i have 51 questions so this is just the many ones XD
anonymous
  • anonymous
51 in 60 minutes lol
anonymous
  • anonymous
huh
phi
  • phi
if you clear the denominator (multiply by x-4 ) you can "solve" to get x=4 but really sats way of solving shows no solution with no extraneous value.
mathstudent55
  • mathstudent55
\(\large \dfrac{4}{x-4}=\dfrac{x}{x-4}-\dfrac{4}{3} \) \(\large 3(x - 4)\dfrac{4}{x-4}=3(x - 4)\dfrac{x}{x-4}-3(x - 4)\dfrac{4}{3} \) \(\large 12 = 3x -12x + 48\) \(\large 9x = 36\) \(\large x = 4\) Since x = 4 cause a zero in the denominator, x = 4 is discarded and there is no solution.
anonymous
  • anonymous
ok thank you <3

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