The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work.
My stuff so far: The required value = ( 18 - d)/2 where d = diameter of the basketball.
What else do I put down??

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- anonymous

- katieb

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- anonymous

total room for the ball=18-9.55=8.45inches
if the ball goes through exactly in the center then there will be 8.45/2=4.225inches of room between rim and ball. Is that the correct answer?

- anonymous

(18 - 9.55)/2 = 4.2in, inches between the ball and the rim on each side? Is that it?

- phi

looks good. the answer depends on how many digits they want

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## More answers

- anonymous

Is it in order?? Is it neat enough? And do I have the answer?

- anonymous

I need to write it down, step by step, in order right down to the answer

- phi

It should have a figure with colors and lines and labels
and footnotes.
kidding... it looks good.

- mathstudent55

I would only add the actual calculation of the diameter of the ball based on its diameter.

- anonymous

circumference (C) = 2(pi)r
\( \huge \frac{C}{2\pi} = r \)
\( \huge \frac{30}{2\pi} = r \)
\( \huge r = \frac{30}{2\pi}\)
\( \huge r = 4.77\)
\( \huge d = 4.77 \times 2\)
\( \huge d = 9.54\)

- anonymous

18 - 9.54 = 8.46

- anonymous

Thank you guys xD

- anonymous

oh btw. @phi @mathstudent55 is nixy correct?

- anonymous

8.46 / 2 = 4.23

- anonymous

@Lollygirl217 I am correct.

- mathstudent55

Yes

- mathstudent55

But I prefer the approximation d = 9.55 in.

- anonymous

okay.

- anonymous

Thank you nixy

- anonymous

YW

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