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anonymous
 one year ago
The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work.
My stuff so far: The required value = ( 18  d)/2 where d = diameter of the basketball.
What else do I put down??
anonymous
 one year ago
The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work. My stuff so far: The required value = ( 18  d)/2 where d = diameter of the basketball. What else do I put down??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0total room for the ball=189.55=8.45inches if the ball goes through exactly in the center then there will be 8.45/2=4.225inches of room between rim and ball. Is that the correct answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(18  9.55)/2 = 4.2in, inches between the ball and the rim on each side? Is that it?

phi
 one year ago
Best ResponseYou've already chosen the best response.0looks good. the answer depends on how many digits they want

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it in order?? Is it neat enough? And do I have the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need to write it down, step by step, in order right down to the answer

phi
 one year ago
Best ResponseYou've already chosen the best response.0It should have a figure with colors and lines and labels and footnotes. kidding... it looks good.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0I would only add the actual calculation of the diameter of the ball based on its diameter.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0circumference (C) = 2(pi)r \( \huge \frac{C}{2\pi} = r \) \( \huge \frac{30}{2\pi} = r \) \( \huge r = \frac{30}{2\pi}\) \( \huge r = 4.77\) \( \huge d = 4.77 \times 2\) \( \huge d = 9.54\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh btw. @phi @mathstudent55 is nixy correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Lollygirl217 I am correct.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0But I prefer the approximation d = 9.55 in.
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