## anonymous one year ago The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work. My stuff so far: The required value = ( 18 - d)/2 where d = diameter of the basketball. What else do I put down??

1. anonymous

total room for the ball=18-9.55=8.45inches if the ball goes through exactly in the center then there will be 8.45/2=4.225inches of room between rim and ball. Is that the correct answer?

2. anonymous

(18 - 9.55)/2 = 4.2in, inches between the ball and the rim on each side? Is that it?

3. phi

looks good. the answer depends on how many digits they want

4. anonymous

Is it in order?? Is it neat enough? And do I have the answer?

5. anonymous

I need to write it down, step by step, in order right down to the answer

6. phi

It should have a figure with colors and lines and labels and footnotes. kidding... it looks good.

7. mathstudent55

I would only add the actual calculation of the diameter of the ball based on its diameter.

8. anonymous

circumference (C) = 2(pi)r $$\huge \frac{C}{2\pi} = r$$ $$\huge \frac{30}{2\pi} = r$$ $$\huge r = \frac{30}{2\pi}$$ $$\huge r = 4.77$$ $$\huge d = 4.77 \times 2$$ $$\huge d = 9.54$$

9. anonymous

18 - 9.54 = 8.46

10. anonymous

Thank you guys xD

11. anonymous

oh btw. @phi @mathstudent55 is nixy correct?

12. anonymous

8.46 / 2 = 4.23

13. anonymous

@Lollygirl217 I am correct.

14. mathstudent55

Yes

15. mathstudent55

But I prefer the approximation d = 9.55 in.

16. anonymous

okay.

17. anonymous

Thank you nixy

18. anonymous

YW