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AmTran_Bus

  • one year ago

polar to cartesian

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  1. AmTran_Bus
    • one year ago
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    |dw:1438548200518:dw|

  2. AmTran_Bus
    • one year ago
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    I know x=rcos theta and y=rsin theta

  3. anonymous
    • one year ago
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    i can help

  4. AmTran_Bus
    • one year ago
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    cool!

  5. amistre64
    • one year ago
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    you are given r and theta ... whats left for you to do?

  6. AmTran_Bus
    • one year ago
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    Well, um, I am given theta? I guess I need more guidance..

  7. amistre64
    • one year ago
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    p = (r,t) and x = r cos(t) y = r sin(t)

  8. AmTran_Bus
    • one year ago
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    Ok. I did not spend much time on this section, but integration techneiques and log stuff got most of my attention. So you are saying it is (5,0) then?

  9. AmTran_Bus
    • one year ago
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    This is final exam review.

  10. amistre64
    • one year ago
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    what is 5 cos(pi/2) ?

  11. amistre64
    • one year ago
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    |dw:1438548585892:dw|

  12. AmTran_Bus
    • one year ago
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    SORRY! 0!!!!!

  13. AmTran_Bus
    • one year ago
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    cos (pi/2) is 0 so 5*0 is 0.

  14. amistre64
    • one year ago
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    (x,y) -> (0,5)

  15. AmTran_Bus
    • one year ago
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    Nice. Thanks.

  16. amistre64
    • one year ago
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    you simply had (y,x) instead of (x,y)

  17. AmTran_Bus
    • one year ago
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    Yea, that way from looking at the possible answer choices and typing before thinking.

  18. AmTran_Bus
    • one year ago
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    *was

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