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anonymous
 one year ago
I need help with this problem trying to figure out how to do it, plz help. I will give medal.
anonymous
 one year ago
I need help with this problem trying to figure out how to do it, plz help. I will give medal.

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phi
 one year ago
Best ResponseYou've already chosen the best response.1if you have a "cube root" then if you multiply it by itself *three times* , you "get rid" of the the radical when they say "rationalized denominator" it means get rid of the radical in the bottom part of the fraction so to do that, multiply the bottom by \(\sqrt[3]{6} \sqrt[3]{6} \) and to keep things equal , you have to multiply the top by the same thing you get \[ \frac{\sqrt[3]{2} \sqrt[3]{6} \sqrt[3]{6} }{\sqrt[3]{6} \sqrt[3]{6} \sqrt[3]{6} } \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1by definition, the bottom becomes 6 (the cube root multiplied three times undoes the radical)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why would you multiply the numerator and the denominator twice by the denominator

phi
 one year ago
Best ResponseYou've already chosen the best response.1in the top, all three are cube roots so you can combine the top into \[ \sqrt[3]{2\cdot 6 \cdot 6} \] I would factor the 6 into 2*3 so we can write the top as \[ \sqrt[3]{2\cdot 2 \cdot 3 \cdot 2 \cdot 3} \] or reordering to make it clearer \[ \sqrt[3]{2\cdot 2 \cdot 2 \cdot 3 \cdot 3} \] now if we find *three of the same term* inside a cube root. we can "pull them out" and replace them with 1 term on the outside \[2 \sqrt[3]{3\cdot 3} \] so far we have \[ \frac{2 \sqrt[3]{3\cdot 3}}{6} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then multiply the 3's on the inside of the radical

phi
 one year ago
Best ResponseYou've already chosen the best response.1can you finish? we can't do much with the 3's inside (we would need 3 of them to simplify) so I would make them 9 and of course we can simplify 2/6 on the outside

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok I understand how to do it now thankyou very much
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