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anonymous
 one year ago
Does anyone know how to solve a system of equations with 3 variables?
anonymous
 one year ago
Does anyone know how to solve a system of equations with 3 variables?

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Saiyan
 one year ago
Best ResponseYou've already chosen the best response.0if you have windows and your on an online school you can use snipping tool to take a pic of it and post it here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x+2yz=3 2x2y+2z=8 2xy+3z=9

Saiyan
 one year ago
Best ResponseYou've already chosen the best response.0you can use substitution or elimination

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0if we define x in terms of y and z, we can use that in the other 2 equations ... and it reduces to a system of 2 equations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now what do I do? @rishavraj

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1ok see lets use elimination method.....we will eliminate "x" x + 2y  z = 3 > say 1st equation 2x  2y + 2z = 8 which is also x  y + z = 4 > say 2nd equation 2x  y + 3z = 9 > say 3rd equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, I'm getting it:)

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1now multiply 2nd equation from 1 and add the new equation with 1st equation..... "x" gets eliminated...... did u understand??

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1so whts the equation u got??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 3x+z=5 and 5x+5z=15 for the 2nd equation

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1hmmmmmmm _ wht u did ???? i askd to eliminate "x" the 1st equation is x + 2y  z = 3 and when u multiply 2nd equation from 1 u get x + y  z = 4now add these two equations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! I used subsitution!

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1its 3y  2z = 7 >say 4th equation

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1hey hold on...... wht were the values u got...the answer ??

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1bco if u meant x = 1 y = 1 and z = 2 then thts correct :)) @SydneyMay17

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes! I did! <3 Thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@rishavraj Sorry, I had to eat dinner

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1oo cool... not a big deal :))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can I ask another question, if I open a new link?
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