anonymous
  • anonymous
Does anyone know how to solve a system of equations with 3 variables?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Saiyan
  • Saiyan
what is the equation
Saiyan
  • Saiyan
if you have windows and your on an online school you can use snipping tool to take a pic of it and post it here
anonymous
  • anonymous
ok hold on

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anonymous
  • anonymous
x+2y-z=-3 2x-2y+2z=8 2x-y+3z=9
Saiyan
  • Saiyan
you can use substitution or elimination
amistre64
  • amistre64
if we define x in terms of y and z, we can use that in the other 2 equations ... and it reduces to a system of 2 equations
anonymous
  • anonymous
Ok @amistre64
anonymous
  • anonymous
so now what do I do? @rishavraj
rishavraj
  • rishavraj
ok see lets use elimination method.....we will eliminate "x" x + 2y - z = -3 --> say 1st equation 2x - 2y + 2z = 8 which is also x - y + z = 4 ----> say 2nd equation 2x - y + 3z = 9 --> say 3rd equation
anonymous
  • anonymous
Ok, I'm getting it:)
rishavraj
  • rishavraj
now multiply 2nd equation from -1 and add the new equation with 1st equation..... "x" gets eliminated...... did u understand??
anonymous
  • anonymous
Yes! :D
anonymous
  • anonymous
Thanks:)
rishavraj
  • rishavraj
so whts the equation u got??
anonymous
  • anonymous
I got 3x+z=5 and 5x+5z=15 for the 2nd equation
anonymous
  • anonymous
Was I wrong?
rishavraj
  • rishavraj
hmmmmmmm -_- wht u did ???? i askd to eliminate "x" the 1st equation is x + 2y - z = -3 and when u multiply 2nd equation from -1 u get -x + y - z = -4now add these two equations
anonymous
  • anonymous
3y=-7
anonymous
  • anonymous
Oh! I used subsitution!
rishavraj
  • rishavraj
its 3y - 2z = -7 --->say 4th equation
anonymous
  • anonymous
Ok:)
rishavraj
  • rishavraj
hey hold on...... wht were the values u got...the answer ??
rishavraj
  • rishavraj
bco if u meant x = 1 y = -1 and z = 2 then thts correct :)) @SydneyMay17
anonymous
  • anonymous
Yes! I did! <3 Thanks
anonymous
  • anonymous
@rishavraj Sorry, I had to eat dinner
rishavraj
  • rishavraj
oo cool... not a big deal :))
anonymous
  • anonymous
Can I ask another question, if I open a new link?
rishavraj
  • rishavraj
for sure
anonymous
  • anonymous
kk!

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