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anonymous

  • one year ago

Does anyone know how to solve a system of equations with 3 variables?

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  1. Saiyan
    • one year ago
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    what is the equation

  2. Saiyan
    • one year ago
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    if you have windows and your on an online school you can use snipping tool to take a pic of it and post it here

  3. anonymous
    • one year ago
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    ok hold on

  4. anonymous
    • one year ago
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    x+2y-z=-3 2x-2y+2z=8 2x-y+3z=9

  5. Saiyan
    • one year ago
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    you can use substitution or elimination

  6. amistre64
    • one year ago
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    if we define x in terms of y and z, we can use that in the other 2 equations ... and it reduces to a system of 2 equations

  7. anonymous
    • one year ago
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    Ok @amistre64

  8. anonymous
    • one year ago
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    so now what do I do? @rishavraj

  9. rishavraj
    • one year ago
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    ok see lets use elimination method.....we will eliminate "x" x + 2y - z = -3 --> say 1st equation 2x - 2y + 2z = 8 which is also x - y + z = 4 ----> say 2nd equation 2x - y + 3z = 9 --> say 3rd equation

  10. anonymous
    • one year ago
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    Ok, I'm getting it:)

  11. rishavraj
    • one year ago
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    now multiply 2nd equation from -1 and add the new equation with 1st equation..... "x" gets eliminated...... did u understand??

  12. anonymous
    • one year ago
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    Yes! :D

  13. anonymous
    • one year ago
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    Thanks:)

  14. rishavraj
    • one year ago
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    so whts the equation u got??

  15. anonymous
    • one year ago
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    I got 3x+z=5 and 5x+5z=15 for the 2nd equation

  16. anonymous
    • one year ago
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    Was I wrong?

  17. rishavraj
    • one year ago
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    hmmmmmmm -_- wht u did ???? i askd to eliminate "x" the 1st equation is x + 2y - z = -3 and when u multiply 2nd equation from -1 u get -x + y - z = -4now add these two equations

  18. anonymous
    • one year ago
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    3y=-7

  19. anonymous
    • one year ago
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    Oh! I used subsitution!

  20. rishavraj
    • one year ago
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    its 3y - 2z = -7 --->say 4th equation

  21. anonymous
    • one year ago
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    Ok:)

  22. rishavraj
    • one year ago
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    hey hold on...... wht were the values u got...the answer ??

  23. rishavraj
    • one year ago
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    bco if u meant x = 1 y = -1 and z = 2 then thts correct :)) @SydneyMay17

  24. anonymous
    • one year ago
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    Yes! I did! <3 Thanks

  25. anonymous
    • one year ago
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    @rishavraj Sorry, I had to eat dinner

  26. rishavraj
    • one year ago
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    oo cool... not a big deal :))

  27. anonymous
    • one year ago
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    Can I ask another question, if I open a new link?

  28. rishavraj
    • one year ago
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    for sure

  29. anonymous
    • one year ago
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    kk!

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