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anonymous

  • one year ago

Which of the following expressions is the conjugate of a complex number with 2 as the real part and 3i as the imaginary part? 2 + 3i 2 − 3i 3i + 2 3i − 2

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  1. Nnesha
    • one year ago
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    you just need to change the sign of imaginary number

  2. kropot72
    • one year ago
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    http://openstudy.com/study#/updates/55be9af5e4b0332550032fa1

  3. anonymous
    • one year ago
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    here check the answer http://www.agor.io/

  4. CBARREDO1
    • one year ago
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    Don't do it

  5. Nnesha
    • one year ago
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    what?

  6. CBARREDO1
    • one year ago
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    Don't click the link, he thinks he is funny 7-7

  7. CBARREDO1
    • one year ago
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    3i+2

  8. anonymous
    • one year ago
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    lol lameeeee but seriously i need help XD

  9. anonymous
    • one year ago
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    and ive been asking if it's 3i+2 and you are the only one who answered back. so that's the answer??

  10. anonymous
    • one year ago
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    it's 2-3i

  11. Nnesha
    • one year ago
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    read my first comment

  12. anonymous
    • one year ago
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    David was looking at his limousine bill and saw that the total number of miles he has ridden in the car was tracked: Month Miles 5 580 6 695 7 810 8 925 The function representing David's miles per month is f(m) = 115m + 5. What does the 115 represent?

  13. anonymous
    • one year ago
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    what about this?

  14. Nnesha
    • one year ago
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    what about the first one ?

  15. anonymous
    • one year ago
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    2-3i?

  16. anonymous
    • one year ago
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    @Nnesha @CBARREDO1 @AlexandruGuja

  17. Nnesha
    • one year ago
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    looks right

  18. anonymous
    • one year ago
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    what abut the one i posted as well

  19. CBARREDO1
    • one year ago
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    115 is the rate isn't it and 5 is the number of miles at start?

  20. anonymous
    • one year ago
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    its asking what 115 represents

  21. Nnesha
    • one year ago
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    y =mx+b where m is slope which represent = rate of change or how things change

  22. anonymous
    • one year ago
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    so wouldn't it be the miles at the start?

  23. Nnesha
    • one year ago
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    y = mx + b where b is y-intercept which represent starting amount

  24. Nnesha
    • one year ago
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    f(m) = 115m + 5 in this equation b is 5

  25. anonymous
    • one year ago
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    im so confused tbh

  26. Nnesha
    • one year ago
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    why?

  27. anonymous
    • one year ago
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    nvm just skip th one i posted. i have a different on

  28. anonymous
    • one year ago
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    What is the simplified form of the quantity 15 x y squared over x squared minus 5x plus 6 all over the quantity 5 x squared y over 2x squared minus 7x plus 3 ?

  29. anonymous
    • one year ago
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    I am hilarious..

  30. anonymous
    • one year ago
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    no ur not xD

  31. Nnesha
    • one year ago
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    \[\huge\rm \frac{ \frac{ 15xy^2 }{ x^2-5x+6} }{ \frac{ 5x^2y }{ 2x^2-7x +3} }\] like this ?

  32. anonymous
    • one year ago
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    @scenemunster You know you love my presence cx

  33. anonymous
    • one year ago
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    yup and totally lol

  34. anonymous
    • one year ago
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    lol

  35. Nnesha
    • one year ago
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    first of all change division to multiplication multiply the first fraction by reciprocal of the denominator fraction example \[\huge\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } } = \frac{ a }{ b } \times \frac{ d }{ c}\]

  36. anonymous
    • one year ago
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    what goes where?

  37. anonymous
    • one year ago
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    @Nnesha ?

  38. Nnesha
    • one year ago
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    \[\huge\rm \frac{\color{reD}{ \frac{ 15xy^2 }{ x^2-5x+6}} }{\color{blue}{ \frac{ 5x^2y }{ 2x^2-7x +3}} }\] red=first fraction a/b blue= 2nd fraction c/d

  39. anonymous
    • one year ago
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    im so confused

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