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anonymous
 one year ago
Need help in Geometry  Central Angles and Arcs
I cant add an attachment so ill simply explain the diagram. The Circle is parted in three parts. <AOB= 53degrees and <BOC is unknown. OB bisects <AOC. I cant seem to figure out m<BOC. Someone please explain this to me:/
anonymous
 one year ago
Need help in Geometry  Central Angles and Arcs I cant add an attachment so ill simply explain the diagram. The Circle is parted in three parts. <AOB= 53degrees and <BOC is unknown. OB bisects <AOC. I cant seem to figure out m<BOC. Someone please explain this to me:/

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jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0use the [Attach File] blue button to attach it

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0or you can always just post the screenshof ot it at say imgur.com

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0and give us the link to it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OB is a bisector, so that means AOB = BOC

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then AOC = AOB + BOC

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you're saying BOC = 53degrees :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you did then wouldn't that mean i could multiply 53 by 6 and get 360

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you don't have to multiply by 6. Add the two 53° angles to get AOC
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