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anonymous
 one year ago
Create an equation. Use the graph below to create the equation of the rainbow parabola.
anonymous
 one year ago
Create an equation. Use the graph below to create the equation of the rainbow parabola.

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rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0so wht do u thiink wht r the roots of the equation???

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0cool......xD means u don't need any help :))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol! I so I got x^2+36 ??

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well... notice whre the vertex is at the vertex is at (0, 36) well.. actaully that's quite close, one sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and there's a 2nd part that I'm not understading

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf y=a(x{\color{brown}{ h}})^2+{\color{blue}{ k}} \qquad vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\) the parabola is upsidedown, meaning the "a" is negative, yes thus \(\bf y=a(x{\color{brown}{ h}})^2+{\color{blue}{ k}} \qquad vertex\ ({\color{brown}{ h}},{\color{blue}{ k}}) \\ \quad \\ y=a(x0)^2+36\implies y=ax^2+36\) we know the roots, thus, when y =0 , x = 6 or 6, let's use 6 so 6, 0 then \(\bf y=ax^2+36\implies \cfrac{y36}{x^2}=a\implies \cfrac{036}{6^2}=a\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, so it would be x^2+36 :)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1ohh yeah, it would, anyhow, kudos :)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1lemme check the other bit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks:) Because I have no idea what to do

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well, is a system of equations lemme see if hmmm lemme graph it

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIteF4yKzM2IiwiY29sb3IiOiIjRTMxMjEyIn0seyJ0eXBlIjowLCJlcSI6IigxLzMpeCsyNSIsImNvbG9yIjoiIzIyMUJFMCJ9LHsidHlwZSI6MTAwMCwid2luZG93IjpbIi0xMy40MjQ4MzUyMDUwNzgxMTgiLCIxMS45NjU3ODk3OTQ5MjE4NjgiLCIyMS4xMDg2MjczMTkzMzU5MzgiLCIzNi43MzM2MjczMTkzMzU5MyJdfV0 you have the "rainbow" parabola and then you're asked to make a LINEar function you're expected to use a table of values for the linear one and to include at least, four values, more is fine so if you use 10 values is ok as well, but not less than 4 values for the table notice the graph.... the LINEar equation graph, crosses the parabola at two points

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you get 1/3x+25?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1made up :), you're expected to make one up, thus

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1I simply made sure the line was secant to the parabola

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1but you can cross the parabola by other lines as well you could simply pick two points, to make a line one on the left, one on the right make sure they "cut" the parabola through, so they touch it at two points and with two points you can get the equation of that line from there you can get more values for the table

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so what would the points be?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well.. let's use the 1/3x + 25 one sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why couldn't we use like 9/5x+20 or 2x+27? And okay, ill wait:)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1either one will work, so long they "cut through" the parabola

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay:) So 9/5x+20 would cut through right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you:)! And to find the points, we could just plug in numbers? or does it have to be specific

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\begin{array}{rrllll} x&y\\ \\\hline\\ 6&\frac{1}{3}\cdot 6+36\\ 4&\frac{1}{3}\cdot 4+36\\ 2&\frac{1}{3}\cdot 2+36\\ 0&\frac{1}{3}\cdot 0+36\\ 2&\frac{1}{3}\cdot 2+36\\ 4&\frac{1}{3}\cdot 4+36\\ 6&\frac{1}{3}\cdot 6+36\\ \end{array}\) there, that'd a table for the blue one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yayyy! :) Lol I finally got it:) Thanks so muchhh
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