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anonymous

  • one year ago

Create an equation. Use the graph below to create the equation of the rainbow parabola.

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  1. anonymous
    • one year ago
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    @rishavraj

  2. rishavraj
    • one year ago
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    so wht do u thiink wht r the roots of the equation???

  3. anonymous
    • one year ago
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    um -6 and 6

  4. rishavraj
    • one year ago
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    cool......xD means u don't need any help :))

  5. anonymous
    • one year ago
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    lol! I so I got -x^2+36 ??

  6. jdoe0001
    • one year ago
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    well... notice whre the vertex is at the vertex is at (0, 36) well.. actaully that's quite close, one sec

  7. anonymous
    • one year ago
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    and there's a 2nd part that I'm not understading

  8. anonymous
    • one year ago
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    Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.

  9. jdoe0001
    • one year ago
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    \(\bf y=a(x-{\color{brown}{ h}})^2+{\color{blue}{ k}} \qquad vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\) the parabola is upside-down, meaning the "a" is negative, yes thus \(\bf y=a(x-{\color{brown}{ h}})^2+{\color{blue}{ k}} \qquad vertex\ ({\color{brown}{ h}},{\color{blue}{ k}}) \\ \quad \\ y=-a(x-0)^2+36\implies y=-ax^2+36\) we know the roots, thus, when y =0 , x = 6 or -6, let's use 6 so 6, 0 then \(\bf y=-ax^2+36\implies \cfrac{y-36}{-x^2}=a\implies \cfrac{0-36}{-6^2}=a\)

  10. anonymous
    • one year ago
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    Yes, so it would be -x^2+36 :)

  11. jdoe0001
    • one year ago
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    ohh yeah, it would, anyhow, kudos :)

  12. jdoe0001
    • one year ago
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    lemme check the other bit

  13. anonymous
    • one year ago
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    Thanks:) Because I have no idea what to do

  14. jdoe0001
    • one year ago
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    well, is a system of equations lemme see if hmmm lemme graph it

  15. anonymous
    • one year ago
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    Ok.

  16. jdoe0001
    • one year ago
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    http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIteF4yKzM2IiwiY29sb3IiOiIjRTMxMjEyIn0seyJ0eXBlIjowLCJlcSI6IigxLzMpeCsyNSIsImNvbG9yIjoiIzIyMUJFMCJ9LHsidHlwZSI6MTAwMCwid2luZG93IjpbIi0xMy40MjQ4MzUyMDUwNzgxMTgiLCIxMS45NjU3ODk3OTQ5MjE4NjgiLCIyMS4xMDg2MjczMTkzMzU5MzgiLCIzNi43MzM2MjczMTkzMzU5MyJdfV0- you have the "rainbow" parabola and then you're asked to make a LINEar function you're expected to use a table of values for the linear one and to include at least, four values, more is fine so if you use 10 values is ok as well, but not less than 4 values for the table notice the graph.... the LINEar equation graph, crosses the parabola at two points

  17. anonymous
    • one year ago
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    how did you get 1/3x+25?

  18. jdoe0001
    • one year ago
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    made up :), you're expected to make one up, thus

  19. jdoe0001
    • one year ago
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    I simply made sure the line was secant to the parabola

  20. jdoe0001
    • one year ago
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    but you can cross the parabola by other lines as well you could simply pick two points, to make a line one on the left, one on the right make sure they "cut" the parabola through, so they touch it at two points and with two points you can get the equation of that line from there you can get more values for the table

  21. anonymous
    • one year ago
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    ok, so what would the points be?

  22. jdoe0001
    • one year ago
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    well.. let's use the 1/3x + 25 one sec

  23. anonymous
    • one year ago
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    why couldn't we use like 9/5x+20 or 2x+27? And okay, ill wait:)

  24. jdoe0001
    • one year ago
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    either one will work, so long they "cut through" the parabola

  25. anonymous
    • one year ago
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    okay:) So 9/5x+20 would cut through right?

  26. anonymous
    • one year ago
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    Thank you:)! And to find the points, we could just plug in numbers? or does it have to be specific

  27. jdoe0001
    • one year ago
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    \(\begin{array}{rrllll} x&y\\ \\\hline\\ -6&\frac{1}{3}\cdot -6+36\\ -4&\frac{1}{3}\cdot -4+36\\ -2&\frac{1}{3}\cdot -2+36\\ 0&\frac{1}{3}\cdot 0+36\\ 2&\frac{1}{3}\cdot 2+36\\ 4&\frac{1}{3}\cdot 4+36\\ 6&\frac{1}{3}\cdot 6+36\\ \end{array}\) there, that'd a table for the blue one

  28. jdoe0001
    • one year ago
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    yw

  29. anonymous
    • one year ago
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    Yayyy! :) Lol I finally got it:) Thanks so muchhh

  30. jdoe0001
    • one year ago
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    np

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