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anonymous
 one year ago
How many grams of pure NaOH must be used to prepare 10.0 L of a solution that has a pH of 13?
anonymous
 one year ago
How many grams of pure NaOH must be used to prepare 10.0 L of a solution that has a pH of 13?

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JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.01.0x10^14=[H+][OH]

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Any ideas on how to use these formulas for this problem?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0Hey , The 1st thing to pop when u read this question is that we can't do anything with pH since it is a base. So u have to find a way to get the pOH from pH for that we can use the following, \[14 =pH+pOH\] (since they haven't given us any detail about the temp and pressure, we will take it at stp so ) Now we found that pOH is equal to 1413= 1

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0Now we can find the concentration of OH using \[pOH = \log_{10}[OH ^{}]\] So will be getting an answer around 0.1 moldm3 So now we know the concentration of OH and we also know the volume of of it which 10L Now using \[C * V= n\] find the no. of moles (n), which will be 1mol We know the no. of moles of OH is equal to the no. of moles of NaOH Now using \[n=\frac{ m }{ M _{w} }\] find the mass (m). As we know the r.m.m. of NaOH which is 40gmol1 So the mass of NaOH will be 1mol x 40gmol1 which is equal to 40gmole again ! simple right? HOpe u got it
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