anonymous
  • anonymous
Solve 3x2 + 6x = 8. 1 plus or minus 2 square root 33 the quantity of negative 3 plus or minus I square root 15 all over 3 the quantity of negative 3 plus or minus square root 33 all over 3 1 plus or minus 2 i square root 15
Mathematics
jamiebookeater
  • jamiebookeater
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Sepeario
  • Sepeario
Okay are these 5 different questions? It's really unclear.
Sepeario
  • Sepeario
For the first bit to solve 3x^2 + 6x = 8, have you heard of completing the square?
anonymous
  • anonymous
no the bottom ones are the answer choices

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Sepeario
  • Sepeario
Oh right. So have you heard of completing the square?
anonymous
  • anonymous
no :/
Sepeario
  • Sepeario
It's a way to solve the trinomial like you have above. I'll show you the steps. \[3x^2+6x=8\] The first step is to move the constant (8) on the other side but that is already done. What you have to do now is to take half the coefficient of x and add it to both sides. Can you do that?
anonymous
  • anonymous
idk how.... man i must sound dumb as hell XD
anonymous
  • anonymous
Sepeario
  • Sepeario
Nah this is actually pretty hard.. but very useful when you learn it. In the term 6x, what is the coefficient of x (the number before x essentially).
anonymous
  • anonymous
3?
campbell_st
  • campbell_st
the easiest thing to do is rewrite the equation as \[3x^2 + 6x - 8 = 0\] then use the general quadratic formula for a quadratic \[ax^2 + bx - c = 0\] the formula is \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] your question has a = 3, b - 6 and c = -8 substitute the values and calculate the answers
campbell_st
  • campbell_st
oops b = 6 a typo in the response above.
Sepeario
  • Sepeario
or you could do that.. I like completing the square. if you learn it it's much quicker than substituting values into the formula.
anonymous
  • anonymous
lol you still at this?
anonymous
  • anonymous
must be like a homework marathon
anonymous
  • anonymous
lol 51 questions XD @satellite73
anonymous
  • anonymous
i hope this is like 47 at least
Sepeario
  • Sepeario
what topic is this on?
anonymous
  • anonymous
do what @campbell_st said use \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] with \[a=3,b=6,c=-8\] that is all compute carefully
Sepeario
  • Sepeario
probably quadratics and polynomials and stuff like that
anonymous
  • anonymous
i am i got \[-6\pm \sqrt{132}\6\]
anonymous
  • anonymous
want me to check it?
anonymous
  • anonymous
idk i just want the answer XD
anonymous
  • anonymous
im tired of algebra. its been 3 hours and im still on the same freaking thing!
anonymous
  • anonymous
that is the answer, before you "simplify it" it is probably not one of your answer choices
anonymous
  • anonymous
is one of them \[\frac{-3\pm\sqrt{33}}{3}\]?
anonymous
  • anonymous
yes XD
anonymous
  • anonymous
then pick that one
anonymous
  • anonymous
how many more?
anonymous
  • anonymous
What is the simplified form of 3 over 2x minus 5 + 21 over 8 x squared minus 14x minus 15 ? 6 times the quantity 2 x plus 5 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3 6 times the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3 6 time the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3 6 times the quantity x plus 1 end quantity over the quantity 2x plus 5 end quantity times 4 x plus 3
anonymous
  • anonymous
yikes
anonymous
  • anonymous
those are just answer choices XD
anonymous
  • anonymous
and i think that it is 6 times the quantity x plus 1 end quantity over the quantity 2x minus 5 end quantity times 4 x plus 3
anonymous
  • anonymous
\[\frac{3}{2x-5}+\frac{21}{8x^2-14x-15}\] like that?
anonymous
  • anonymous
yes
anonymous
  • anonymous
i can't read your answer really i know the denominator is correct \[(2x-5)(4x+3)\]
anonymous
  • anonymous
6(x+1)/(2x-5)(4x+3)
anonymous
  • anonymous
What is the simplified form of the quantity 15 x y squared over x squared minus 5x plus 6 all over the quantity 5 x squared y over 2x squared minus 7x plus 3 ? 3y times the quantity 2x plus 1 over x times the quantity x plus 2 x times the quantity x plus 2 over 3y times the quantity 2x plus 1 x times the quantity x minus 2 over 3y times the quantity 2x minus 1 3y times the quantity 2x minus 1 over x times the quantity x minus 2
anonymous
  • anonymous
yikes
anonymous
  • anonymous
hard to read again let me try
anonymous
  • anonymous
XDDD
anonymous
  • anonymous
\[\frac{15xy^2}{x^2-5x+6}\]?
anonymous
  • anonymous
i need a screenshot maybe
anonymous
  • anonymous
idk how to do that
anonymous
  • anonymous
hit "print screen" on your keyboard, then attach it
anonymous
  • anonymous
anonymous
  • anonymous
it's not working...
anonymous
  • anonymous
ok give me a second was any part of what i wrote correct?
anonymous
  • anonymous
i bet it was a compound fraction which amounts to \[\frac{15xy^2}{x^2-5x+6}\times \frac{2x^2-7x+3}{5x^2y}\]
anonymous
  • anonymous
|dw:1438565010844:dw|
anonymous
  • anonymous
yeah what i wrote
anonymous
  • anonymous
"invert and multiply" and get \[\frac{15xy^2}{x^2-5x+6}\times \frac{2x^2-7x+3}{5x^2y}\] as a first step
anonymous
  • anonymous
then cancel some stuff, not much goes though
anonymous
  • anonymous
i don't understand
anonymous
  • anonymous
when you divide by a fraction you "invert and multiply" just like with numbers
anonymous
  • anonymous
all i did was flip the denominator of the expression you wrote then you can cancel a bit
anonymous
  • anonymous
oh gotcha
anonymous
  • anonymous
\[\frac{3y(2x^2-7x+3)}{x(x^2-5x+6)}\]
anonymous
  • anonymous
nothing else cancels, so either that is the final answer or there is a typo
anonymous
  • anonymous
that cant be
anonymous
  • anonymous
ok i need something better sure you cannot take a screen shot?
anonymous
  • anonymous
3y times the quantity 2x plus 1 over x times the quantity x plus 2 this is the closest thing to that
Sepeario
  • Sepeario
are you on a mac or windows?
anonymous
  • anonymous
windows
Sepeario
  • Sepeario
is there a prt scr button?
anonymous
  • anonymous
yes and i pressed it multiple times and it doesnt wrk
anonymous
  • anonymous
ok i think i got it
anonymous
  • anonymous
Bob and Susie wash cars for extra money over the summer. Bob's income is determined by f(x) = 6x + 13, where x is the number of hours. Susie's income is g(x) = 4x + 18. If Bob and Susie were to combine their efforts, their income would be h(x) = f(x) + g(x). Assume Bob works 3 hours. Create the function h(x) and indicate if Bob will make more money working alone or by teaming with Susie. A h(x) = 2x + 5, work alone B h(x) = 2x + 5, team with Susie C h(x) = 10x + 31, team with Susie D h(x) = 10x + 31, work alone
anonymous
  • anonymous
lol i have seen this exact silly question before
anonymous
  • anonymous
\[h(x)=f(x)+g(x)=6x+13+4x+18\]
anonymous
  • anonymous
combine like terms and get \[h(x)=10x+31\]
anonymous
  • anonymous
yea but would that be team with susie or work alone?
anonymous
  • anonymous
hmm depends
anonymous
  • anonymous
\[f(3)=6\times 3+13=31\]
anonymous
  • anonymous
\[h(3)=10\times 3+31=61\]
anonymous
  • anonymous
if he has to split the money with susie he is better off working alone
anonymous
  • anonymous
lol okaiis
anonymous
  • anonymous
i can tell the end is in sight
anonymous
  • anonymous
A function is created to represent the costs of living per person in the family. What restrictions would be made to the domain?
anonymous
  • anonymous
i guess it would have to be greater than or equal to zero
anonymous
  • anonymous
A.The domain would only include integers. B.The domain would only include positive integers. C.The domain would only include positive numbers. D.The domain would include all real numbers.
anonymous
  • anonymous
i am going to make a guess, because none of this really makes too much sense
anonymous
  • anonymous
make it a good guess XD
anonymous
  • anonymous
A and B are clearly wrong, since it could be decimals (it is money after all)
anonymous
  • anonymous
i would go with C
anonymous
  • anonymous
can't imagine the cost of living is negative
anonymous
  • anonymous
i only make good guesses they are, however, just guesses
anonymous
  • anonymous
To which graph does the point (−1, 3) belong? A.y ≥ 2x + 6 B.y ≥ 3x − 1 C.y ≥ −x + 4 D.y ≥ −2x + 5
anonymous
  • anonymous
idk lets try the first one is \[3\geq 2(-1)+6\]?
anonymous
  • anonymous
nope you would have \[3\geq 4\]which is false
anonymous
  • anonymous
this makes no sense
anonymous
  • anonymous
sure it does
anonymous
  • anonymous
\((-1,3)\) is your \((x,y)\)
anonymous
  • anonymous
so to see if it satisfies \[y\geq 3x-1\] put \(x=-1\) and \(y=3\) and see if the inequality is right or wrong
anonymous
  • anonymous
thsts what i thought
anonymous
  • anonymous
you get \[3\geq 3(-1)-1\] or \[3\geq -4\] which is definitely true
anonymous
  • anonymous
so at least that one is right can there be more than one answer?
anonymous
  • anonymous
im done :D Let's see what i get!
anonymous
  • anonymous
DONE!! its about time
anonymous
  • anonymous
71%!!!!! :D
anonymous
  • anonymous
now get away from the computer, stop doing math
anonymous
  • anonymous
is that all?
anonymous
  • anonymous
lol i might do one more XD
anonymous
  • anonymous
should have got at least 95 with all the brilliant help you have been getting
anonymous
  • anonymous
go have a beer, do it tomorrow if you are too young to have a beer, have a snack
anonymous
  • anonymous
Simplify completely quantity x squared plus 12 x plus 35 all over 3 x plus 15.
anonymous
  • anonymous
quantity of x squared plus 21 over 3 quantity of x squared plus 11 over 3 quantity x plus 7 over 3 quantity of x plus 5 over 3
anonymous
  • anonymous
just one more CX
anonymous
  • anonymous
one more assignment i mean CX
anonymous
  • anonymous
one more question for me
anonymous
  • anonymous
awh man CX you're the only one responding CX
anonymous
  • anonymous
\[\frac{x^2+12x+35}{3x+15}=\frac{(x+5)(x+7)}{3(x+5)}\] \[=\frac{x+7}{3}\]
anonymous
  • anonymous
got it cx
anonymous
  • anonymous
take a break for heaven's sake i went out, had dinner, watched an episode of columbo, and you were still here
Sepeario
  • Sepeario
^^ that rhymed
pooja195
  • pooja195
This is just sad.
anonymous
  • anonymous
cx how is this sad CX
pooja195
  • pooja195
It just is.

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