zeesbrat3 one year ago A particle moves on a line away from its initial position so that after t hours it is s = 2t2 +3t miles from its initial position. Find the average velocity of the particle over the interval [1, 4].

1. zeesbrat3

@jim_thompson5910

2. zeesbrat3

@ganeshie8

3. jim_thompson5910

Position function $\Large f(t) = 2t^2+3t$ Velocity function (apply derivative) $\Large v(t) = f \ ' (t) = 4t+3$ A = average velocity $\Large A = \frac{1}{b-a}\int_{a}^{b}(v(t)dt)$ $\Large A = \frac{1}{4-1}\int_{1}^{4}(4t+3)dt$ I'll let you finish.