## anonymous one year ago Solving for x: (x^2- a^2)= 3(x+a)

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1. anonymous

$x^2-a^2-3\left( x+a \right)=0$ $\left( x+a \right)\left( x-a \right)-3\left( x+a \right)=0$ $\left( x+a \right)\left( x-a-3 \right)=0$ equate each factor to 0 and find x

2. anonymous

How do you get from (x+a)(x-a)-3(x+a)=0 to (x+a)(x-a-3)=0 ??

3. anonymous

$a^2-b^2=\left( a+b \right)\left( a-b \right)$ i have taken x+a common from both factors.