anonymous
  • anonymous
Medal for this please Part A: Solve A = 9 over 2 (x + 23) for x. Part B: Determine the value of x when A = 108. Part C: Solve -np - 90 > 30 for n. Show your work
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@triciaal
anonymous
  • anonymous
any idea?
anonymous
  • anonymous
Part A: \[A = \frac{ 9 }{ 2(x+23) }\]

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anonymous
  • anonymous
Okay so first lets distribute the 2 to x and 23. What would you get?
anonymous
  • anonymous
2x and 46
anonymous
  • anonymous
is this for part B?
anonymous
  • anonymous
No, this is for Part A. We have to solve for x. We haven't done that yet.
anonymous
  • anonymous
Anyways so yes you get 2x + 46
anonymous
  • anonymous
So now it looks like: \[A = \frac{ 9 }{ 2x + 46 }\]
anonymous
  • anonymous
so do we add 46 and 9?
anonymous
  • anonymous
No don't add.
anonymous
  • anonymous
multiply
anonymous
  • anonymous
so 414?
anonymous
  • anonymous
then divide it by 2
anonymous
  • anonymous
Wait hold up. Don't multiply either. I'll tell you.
anonymous
  • anonymous
okay sorry haha
anonymous
  • anonymous
Okay so lets multiply 2x + 46 on both sides. \[A(2x+46) = \frac{ 9 }{ 2x+46 }(2x+46)\]
anonymous
  • anonymous
This cancels out 2x + 46 on the right side. And we have to then distribute the A to 2x and 46. \[2xA + 46A = 9\]
anonymous
  • anonymous
So far so good?
anonymous
  • anonymous
We have to find a common factor between 2xA and 46A. The common factor would be 2A since both coefficients are divisible by 2 and A. It would look like this now: \[2A(x+23) = 9\]
anonymous
  • anonymous
We have to divide 2A on both sides. \[\frac{ 2A(x+23) }{ 2A } = \frac{ 9 }{ 2A }\]
anonymous
  • anonymous
okay got it so far
anonymous
  • anonymous
This cancels out 2A on the left side. Now the equation looks like this: \[x + 23 = \frac{ 9 }{ 2A }\] Now we can isolate x by subtracting 23 from both sides. \[x + 23 -23 = \frac{ 9 }{ 2A }-23\] Now, x solved is \[x = \frac{ 9 }{ 2A }-23\], which is the answer to PART A.
anonymous
  • anonymous
For Part B, just substitute 108 for A in \[x = \frac{ 9 }{ 2A }-23\] What would you get for the value of x?
anonymous
  • anonymous
its like doing part A but plugging in 108 instead of (x + 23)?
anonymous
  • anonymous
Yes basically
anonymous
  • anonymous
So what is the value of x for Part B?
anonymous
  • anonymous
okay i can do it from here thank you :)
anonymous
  • anonymous
Alright then. No problem:)

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