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anonymous
 one year ago
Medal for this please
Part A: Solve A = 9 over 2 (x + 23) for x.
Part B: Determine the value of x when A = 108.
Part C: Solve np  90 > 30 for n. Show your work
anonymous
 one year ago
Medal for this please Part A: Solve A = 9 over 2 (x + 23) for x. Part B: Determine the value of x when A = 108. Part C: Solve np  90 > 30 for n. Show your work

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part A: \[A = \frac{ 9 }{ 2(x+23) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so first lets distribute the 2 to x and 23. What would you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, this is for Part A. We have to solve for x. We haven't done that yet.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyways so yes you get 2x + 46

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now it looks like: \[A = \frac{ 9 }{ 2x + 46 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so do we add 46 and 9?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait hold up. Don't multiply either. I'll tell you.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so lets multiply 2x + 46 on both sides. \[A(2x+46) = \frac{ 9 }{ 2x+46 }(2x+46)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This cancels out 2x + 46 on the right side. And we have to then distribute the A to 2x and 46. \[2xA + 46A = 9\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We have to find a common factor between 2xA and 46A. The common factor would be 2A since both coefficients are divisible by 2 and A. It would look like this now: \[2A(x+23) = 9\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We have to divide 2A on both sides. \[\frac{ 2A(x+23) }{ 2A } = \frac{ 9 }{ 2A }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This cancels out 2A on the left side. Now the equation looks like this: \[x + 23 = \frac{ 9 }{ 2A }\] Now we can isolate x by subtracting 23 from both sides. \[x + 23 23 = \frac{ 9 }{ 2A }23\] Now, x solved is \[x = \frac{ 9 }{ 2A }23\], which is the answer to PART A.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For Part B, just substitute 108 for A in \[x = \frac{ 9 }{ 2A }23\] What would you get for the value of x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its like doing part A but plugging in 108 instead of (x + 23)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what is the value of x for Part B?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i can do it from here thank you :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright then. No problem:)
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