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anonymous

  • one year ago

Medal for this please Part A: Solve A = 9 over 2 (x + 23) for x. Part B: Determine the value of x when A = 108. Part C: Solve -np - 90 > 30 for n. Show your work

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  1. anonymous
    • one year ago
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    @triciaal

  2. anonymous
    • one year ago
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    any idea?

  3. anonymous
    • one year ago
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    Part A: \[A = \frac{ 9 }{ 2(x+23) }\]

  4. anonymous
    • one year ago
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    Okay so first lets distribute the 2 to x and 23. What would you get?

  5. anonymous
    • one year ago
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    2x and 46

  6. anonymous
    • one year ago
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    is this for part B?

  7. anonymous
    • one year ago
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    No, this is for Part A. We have to solve for x. We haven't done that yet.

  8. anonymous
    • one year ago
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    Anyways so yes you get 2x + 46

  9. anonymous
    • one year ago
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    So now it looks like: \[A = \frac{ 9 }{ 2x + 46 }\]

  10. anonymous
    • one year ago
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    so do we add 46 and 9?

  11. anonymous
    • one year ago
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    No don't add.

  12. anonymous
    • one year ago
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    multiply

  13. anonymous
    • one year ago
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    so 414?

  14. anonymous
    • one year ago
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    then divide it by 2

  15. anonymous
    • one year ago
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    Wait hold up. Don't multiply either. I'll tell you.

  16. anonymous
    • one year ago
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    okay sorry haha

  17. anonymous
    • one year ago
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    Okay so lets multiply 2x + 46 on both sides. \[A(2x+46) = \frac{ 9 }{ 2x+46 }(2x+46)\]

  18. anonymous
    • one year ago
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    This cancels out 2x + 46 on the right side. And we have to then distribute the A to 2x and 46. \[2xA + 46A = 9\]

  19. anonymous
    • one year ago
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    So far so good?

  20. anonymous
    • one year ago
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    We have to find a common factor between 2xA and 46A. The common factor would be 2A since both coefficients are divisible by 2 and A. It would look like this now: \[2A(x+23) = 9\]

  21. anonymous
    • one year ago
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    We have to divide 2A on both sides. \[\frac{ 2A(x+23) }{ 2A } = \frac{ 9 }{ 2A }\]

  22. anonymous
    • one year ago
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    okay got it so far

  23. anonymous
    • one year ago
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    This cancels out 2A on the left side. Now the equation looks like this: \[x + 23 = \frac{ 9 }{ 2A }\] Now we can isolate x by subtracting 23 from both sides. \[x + 23 -23 = \frac{ 9 }{ 2A }-23\] Now, x solved is \[x = \frac{ 9 }{ 2A }-23\], which is the answer to PART A.

  24. anonymous
    • one year ago
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    For Part B, just substitute 108 for A in \[x = \frac{ 9 }{ 2A }-23\] What would you get for the value of x?

  25. anonymous
    • one year ago
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    its like doing part A but plugging in 108 instead of (x + 23)?

  26. anonymous
    • one year ago
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    Yes basically

  27. anonymous
    • one year ago
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    So what is the value of x for Part B?

  28. anonymous
    • one year ago
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    okay i can do it from here thank you :)

  29. anonymous
    • one year ago
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    Alright then. No problem:)

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