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-Welp-

  • one year ago

Is this correct? "the area of sector AOC is 20.25pi ft^. Find the area of the shaded part of the segment.

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  1. -Welp-
    • one year ago
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    |dw:1438569953793:dw| Area of Segment = ½ × (θ - sin θ) × r2 1/2 * (90-sin(90)*9^2=4.5 20.25 - 4.5=15.75

  2. jim_thompson5910
    • one year ago
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    You mentioned point C when you said AOC but I don't see a point C on the drawing

  3. -Welp-
    • one year ago
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    I meant to put C instead of B in the drawing

  4. jim_thompson5910
    • one year ago
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    Ok so what you need to do is find the area of the triangle, then subtract that from the area of the sector Shaded region = (area of sector) - (area of triangle)

  5. -Welp-
    • one year ago
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    How do I find the triangle? I've only been given one side and no angles.

  6. jim_thompson5910
    • one year ago
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    the two legs of the right triangle are congruent because all radii of the same circle are congruent |dw:1438570809227:dw|

  7. -Welp-
    • one year ago
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    Oh, thanks!

  8. jim_thompson5910
    • one year ago
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    no problem

  9. jim_thompson5910
    • one year ago
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    btw your formula would work only if theta is in radians as explained here http://mathworld.wolfram.com/CircularSegment.html

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