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wampominater
 one year ago
Find the angle between the given vectors to the nearest tenth of a degree.
u = <5, 4>, v = <4, 3>
wampominater
 one year ago
Find the angle between the given vectors to the nearest tenth of a degree. u = <5, 4>, v = <4, 3>

This Question is Closed

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1so far, i have followed the formula \[\cos(\theta) = \frac{ u*v }{\left v \right \left u \right }\] and i have gotten 1, but that isnt an answer choice...

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1and then when I take the arc cos of 1, I get 0, which is not a choice

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge u = \sqrt{(5)^2+(4)^2} = \sqrt{41} \) \( \huge v = \sqrt{(4)^2+(3)^2} = 5 \) That what you have for v and u ?

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1yeah, i believe i know what i did wrong now though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you sure? I can work it out if you want

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1well, i think that its because i rounded the denom to 32

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1but sure, if you want to help me do it just to make sure, thatd be great! :)

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1so i got approx 1.8 when i didnt round the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We should have \( \huge \cos(\theta) = \frac{ u*v }{\left v \right \left u \right }\) \( \huge \cos(\theta) = \frac{ 32}{\left 5 \right \left \sqrt{41} \right } = .99951 = 1.78 degrees\) That is what I got.

wampominater
 one year ago
Best ResponseYou've already chosen the best response.1awesome, that is what i got too, thank you for the help!
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