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anonymous
 one year ago
Find the angle between the given vectors to the nearest tenth of a degree.
u = <5, 4>, v = <4, 3>
anonymous
 one year ago
Find the angle between the given vectors to the nearest tenth of a degree. u = <5, 4>, v = <4, 3>

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so far, i have followed the formula \[\cos(\theta) = \frac{ u*v }{\left v \right \left u \right }\] and i have gotten 1, but that isnt an answer choice...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then when I take the arc cos of 1, I get 0, which is not a choice

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge u = \sqrt{(5)^2+(4)^2} = \sqrt{41} \) \( \huge v = \sqrt{(4)^2+(3)^2} = 5 \) That what you have for v and u ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, i believe i know what i did wrong now though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you sure? I can work it out if you want

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, i think that its because i rounded the denom to 32

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but sure, if you want to help me do it just to make sure, thatd be great! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i got approx 1.8 when i didnt round the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We should have \( \huge \cos(\theta) = \frac{ u*v }{\left v \right \left u \right }\) \( \huge \cos(\theta) = \frac{ 32}{\left 5 \right \left \sqrt{41} \right } = .99951 = 1.78 degrees\) That is what I got.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0awesome, that is what i got too, thank you for the help!
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