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anonymous
 one year ago
if x^2 = 2x + 6 ... i need to solve for x.
anonymous
 one year ago
if x^2 = 2x + 6 ... i need to solve for x.

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arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0=>X^22x6=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use the Quadratic Formula to find the values of x

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1a ,b , c values are \[\huge\rm Ax^2+Bx+C=0\] where a =leading coefficient b= leading coefficient c= constant term \[\huge~\rm~x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x^22x+1)=6+1 (x1)^2=7 now you can solve it.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0then use quadratic formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2 2x 6 = 0 \] is in the form of \[ax^2 + bx + c = 0\] where a = 1, b = 2, and c = 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simply plug those numbers into the Quadratic Formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think im maybe misunderstanding what im supposed to do? the problem is if x^2= 2x +6 then x can equal (A) 2  the square root of 28 (B) 1  the square root of 28 (C) 1  2 root 7 (D) 1  root 7 and none of the above.. i do have to solve for x right? i feel like im missing something
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