## anonymous one year ago if x^2 = 2x + 6 ... i need to solve for x.

1. arindameducationusc

=>X^2-2x-6=0

2. anonymous

You can use the Quadratic Formula to find the values of x

3. pooja195

a ,b , c values are $\huge\rm Ax^2+Bx+C=0$ where a =leading coefficient b= leading coefficient c= constant term $\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$

4. arindameducationusc
5. anonymous

(x^2-2x+1)=6+1 (x-1)^2=7 now you can solve it.

6. arindameducationusc

7. anonymous

$x^2 -2x -6 = 0$ is in the form of $ax^2 + bx + c = 0$ where a = 1, b = -2, and c = -6

8. anonymous

Simply plug those numbers into the Quadratic Formula

9. anonymous

i think im maybe misunderstanding what im supposed to do? the problem is if x^2= 2x +6 then x can equal (A) 2 - the square root of 28 (B) 1 - the square root of 28 (C) 1 - 2 root 7 (D) 1 - root 7 and none of the above.. i do have to solve for x right? i feel like im missing something