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anonymous

  • one year ago

Help !!!

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  1. anonymous
    • one year ago
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    \[4 \tan \theta = 3 find : \frac{ 4 \sin \theta - \cos \theta }{ { 4 \sin \theta + \cos \theta } }\]

  2. arindameducationusc
    • one year ago
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    E|dw:1438595156291:dw|

  3. arindameducationusc
    • one year ago
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    |dw:1438595205018:dw|

  4. arindameducationusc
    • one year ago
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    so, putting the value of tan theta let theta=x sec(^2)x=1+tan(^2)x =1+(3/4)^2 secx=5/4 so cos x=4/5

  5. arindameducationusc
    • one year ago
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    now find sin x by 1-cos^x and put cos and sin the your equation. If you have any doubt ask me okay? @Greaty

  6. anonymous
    • one year ago
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    ._. ok suu this was on me test so i will help ya

  7. anonymous
    • one year ago
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    First of all:\[\tan=\frac{ \sin \theta }{ \cos \theta}\]

  8. anonymous
    • one year ago
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    1=\[\sin \theta+\cos \theta\]

  9. anonymous
    • one year ago
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    base your equation off this information

  10. anonymous
    • one year ago
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    @arindameducationusc \[\tan \theta\] never equaled \[\frac{ 3 }{ 4 }\]

  11. Michele_Laino
    • one year ago
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    hint: If we divide both numerator and denominator by cos(\theta), we get: \[\Large \frac{{4\sin \theta - \cos \theta }}{{4\sin \theta + \cos \theta }} = \frac{{\frac{{4\sin \theta - \cos \theta }}{{\cos \theta }}}}{{\frac{{4\sin \theta + \cos \theta }}{{\cos \theta }}}} = \frac{{4\tan \theta - 1}}{{4\tan \theta + 1}}\]

  12. Michele_Laino
    • one year ago
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    therefore, after a substitution, we can write this: \[\Large \begin{gathered} \frac{{4\sin \theta - \cos \theta }}{{4\sin \theta + \cos \theta }} = \frac{{\frac{{4\sin \theta - \cos \theta }}{{\cos \theta }}}}{{\frac{{4\sin \theta + \cos \theta }}{{\cos \theta }}}} = \frac{{4\tan \theta - 1}}{{4\tan \theta + 1}} = \hfill \\ \hfill \\ = \frac{{\left( {4 \times \frac{3}{4}} \right) - 1}}{{\left( {4 \times \frac{3}{4}} \right) + 1}} = ...? \hfill \\ \end{gathered} \]

  13. arindameducationusc
    • one year ago
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    @Icedragon Are you okay???

  14. IrishBoy123
    • one year ago
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    OR|dw:1438603742502:dw| and just do it in your head :-)

  15. anonymous
    • one year ago
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    thanks all :)

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