At a school carnival, the diameter of the mat of a trampoline is 10 feet and the diameter of its metal frame is 12 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth.

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At a school carnival, the diameter of the mat of a trampoline is 10 feet and the diameter of its metal frame is 12 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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does anyone understand
I think that the requested length is given by the subsequent formula: \[\Large L = 2 \times 3.14 \times \frac{d}{2}\] where d= 12 feet
oh

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hint: \[\Large L = 2 \times 3.14 \times \frac{d}{2} = 2 \times 3.14 \times \frac{{12}}{2} = ...?\]
I agree @Michele_Laino @bubbleslove1234 As they are talking about a circle kind of like thingy, when they ask the surrounding it is gonna be the circumference of the circle. So we are able to use this equation \[C= 2\pi r\]
where as r is the radius of the circle. ! Hence we can substitute it to \[\frac{ d }{ 2}\]
Hope u understood me

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