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anonymous

  • one year ago

1) When the sum of 5 and twice a positive number is subtracted from the square of the number, 0 results. Find the number.

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  1. pooja195
    • one year ago
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    Let x be the number First thing it says is subtracted from the square of A NUMER (x) sooo \[\huge~\rm~x^2- \]

  2. pooja195
    • one year ago
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    *number

  3. pooja195
    • one year ago
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    Then it says the number is twice postivie soo 2x and the sum (adding) of 5 so it would look like this \[\huge~\rm~(2x+5)\]

  4. pooja195
    • one year ago
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    The result is 0 so =0 \[\huge~\rm~x^2-(2x+5)=0 \]

  5. pooja195
    • one year ago
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    We can remove the parentheses and write it like this: \[\huge~\rm~x^2-2x-5=0 \]

  6. pooja195
    • one year ago
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    Find the abc values :) a ,b , c values are \[\huge\rm Ax^2+Bx+C=0\] where a =leading coefficient b= leading coefficient c= constant term

  7. anonymous
    • one year ago
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    a=1 b=2 c=5

  8. anonymous
    • one year ago
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    -2 -5

  9. pooja195
    • one year ago
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    Good : )

  10. pooja195
    • one year ago
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    \[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

  11. anonymous
    • one year ago
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    \[x=\frac{ 2\pm \sqrt{2^2-4(1)(5)} }{ 2(1) }\]

  12. pooja195
    • one year ago
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    \[\huge~\rm~x=\frac{ -(-2) \pm \sqrt{(-2)^2-4(1)(-5)} }{ 2(1) }\]

  13. anonymous
    • one year ago
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    oh in the sqrt its -2

  14. anonymous
    • one year ago
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    and -5 okay

  15. pooja195
    • one year ago
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    ok can you solve whats in the sqrt?

  16. anonymous
    • one year ago
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    \[\sqrt{80}\]

  17. anonymous
    • one year ago
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    \[2\pm4\sqrt{5}\]

  18. pooja195
    • one year ago
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    I got \[\huge~\rm~1±1\sqrt{6}\]

  19. anonymous
    • one year ago
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    ..how?

  20. pooja195
    • one year ago
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    eh i cheated and used a calc ;p heres the work http://prntscr.com/80bm1y

  21. anonymous
    • one year ago
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    what calc did you use

  22. pooja195
    • one year ago
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    http://www.mathwarehouse.com/quadratic/quadratic-formula-calculator.php

  23. pooja195
    • one year ago
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    Then we make 2 seperate equations one plus and one minus since we basically have to split the plus minus sign then u simplfy from here \[\frac{ \huge~\rm~1+1\sqrt{6} }{ \huge~\rm~1 }\] \[\frac{ \huge~\rm~1-1\sqrt{6} }{ \huge~\rm~1 }\]

  24. pooja195
    • one year ago
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    You will end up with ONE positive answer and ONE negative answer. The psotive answer is the answer to the question :)

  25. anonymous
    • one year ago
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    ...

  26. pooja195
    • one year ago
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    ...?

  27. anonymous
    • one year ago
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    how

  28. pooja195
    • one year ago
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    I never learned....:/ you will need to use a calculator or ask someone else...i have always used a calc for this part... @Astrophysics

  29. ali2x2
    • one year ago
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    @ganeshie8

  30. just_one_last_goodbye
    • one year ago
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    @pooja195 what do we want to convert into a decimal?

  31. pooja195
    • one year ago
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    \(\color{#0cbb34}{\text{Originally Posted by}}\) @pooja195 Then we make 2 seperate equations one plus and one minus since we basically have to split the plus minus sign then u simplfy from here \[\frac{ \huge~\rm~1+1\sqrt{6} }{ \huge~\rm~1 }\] \[\frac{ \huge~\rm~1-1\sqrt{6} }{ \huge~\rm~1 }\] \(\color{#0cbb34}{\text{End of Quote}}\) This and show your stpes

  32. pooja195
    • one year ago
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    *steps

  33. just_one_last_goodbye
    • one year ago
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    alright

  34. just_one_last_goodbye
    • one year ago
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    both on top of each other like fractions correct?

  35. ali2x2
    • one year ago
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    @just_one_last_goodbye i think so

  36. pooja195
    • one year ago
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    Actually a better way to solve it Apply this rule \[\huge~\rm~\frac{ a }{ 1 }=a\]

  37. pooja195
    • one year ago
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    \[\huge~\rm~\frac{1+\sqrt{6}1}{1}=1+\sqrt{6}1 \]

  38. pooja195
    • one year ago
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    \[\huge~\rm~1+1\cdot \sqrt{6} \]

  39. pooja195
    • one year ago
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    \[\huge~\rm~1\cdot \:a=a\]

  40. pooja195
    • one year ago
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    \[\huge~\rm~1+\sqrt{6}\]

  41. pooja195
    • one year ago
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    Now turn it into decimal form

  42. pooja195
    • one year ago
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    We dont even need to solve fore the subtraction problem because we know that the number will be negative

  43. anonymous
    • one year ago
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    ok

  44. ali2x2
    • one year ago
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    ill try it myself

  45. just_one_last_goodbye
    • one year ago
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    I got 3.44949

  46. pooja195
    • one year ago
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    Thats right

  47. anonymous
    • one year ago
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    I was gonna ask if we round it to 3.45

  48. pooja195
    • one year ago
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    Yep :)

  49. ali2x2
    • one year ago
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    i got 3.44949

  50. anonymous
    • one year ago
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    okay, thank you for being so patient.

  51. ali2x2
    • one year ago
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    oh they already said that

  52. pooja195
    • one year ago
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    lol

  53. ali2x2
    • one year ago
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    i cri

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