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anonymous

  • one year ago

2) 2/5x^2 -x+ 19/15 =0

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  1. anonymous
    • one year ago
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    lol

  2. just_one_last_goodbye
    • one year ago
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    anyways lets see how i can help

  3. just_one_last_goodbye
    • one year ago
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    is the first 2 part of the equation or no?

  4. anonymous
    • one year ago
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    \[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]

  5. anonymous
    • one year ago
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    I hope that makes it better

  6. just_one_last_goodbye
    • one year ago
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    Much better ^-^

  7. anonymous
    • one year ago
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    So I know A= 2/5 B= -1 C= 19/15

  8. just_one_last_goodbye
    • one year ago
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    Decimal answer correct?

  9. anonymous
    • one year ago
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    yes

  10. just_one_last_goodbye
    • one year ago
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    and Solving for x?

  11. just_one_last_goodbye
    • one year ago
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    x = 1.455485

  12. anonymous
    • one year ago
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    it says "Use the quadratic formula to solve the equation." "A. The solution set is ____" (simplify your answer. type an exact answer, ysing radicals as needed. Use intefers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) "B. the solution is (emptyset)"

  13. just_one_last_goodbye
    • one year ago
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    ~eats pizza while waiting~

  14. anonymous
    • one year ago
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    lol my b

  15. just_one_last_goodbye
    • one year ago
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    ~passes skittles~

  16. anonymous
    • one year ago
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    omg. skittles with coffee

  17. anonymous
    • one year ago
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    yes

  18. just_one_last_goodbye
    • one year ago
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    ^

  19. just_one_last_goodbye
    • one year ago
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    Oh quadratic thought it was a normal equation sorry

  20. anonymous
    • one year ago
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    lol, the only unit i have left is quadratic and I haven't done it in 2 years

  21. just_one_last_goodbye
    • one year ago
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    hmm idk it's not giving me an answer

  22. anonymous
    • one year ago
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    okay it's okay, let's move on to the next question?

  23. just_one_last_goodbye
    • one year ago
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    sure

  24. anonymous
    • one year ago
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    .6x^2 = 1.2x+0.6

  25. anonymous
    • one year ago
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    \[0.6x^2-1.2x-0.6=0\]

  26. just_one_last_goodbye
    • one year ago
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    wait is it an addition problem or subtraction?

  27. anonymous
    • one year ago
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    I just flipped it so it's in standard form. it's still quadratic. just now it's all on one side.

  28. anonymous
    • one year ago
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    ...

  29. just_one_last_goodbye
    • one year ago
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    Open this attachment up, It should help ^-^

    1 Attachment
  30. anonymous
    • one year ago
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    what site did you use?

  31. misty1212
    • one year ago
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    HI!!

  32. just_one_last_goodbye
    • one year ago
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    . - . . _ .

  33. misty1212
    • one year ago
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    \[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\] is annoying multiply by 15 and get \[6x^2-15x+19=0\] then it will be much easier

  34. misty1212
    • one year ago
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    you can use the quadratic formula or if you are a factoring wiz you can try that

  35. anonymous
    • one year ago
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    yeah. I'm on here, asking for help. I'm not a factoring wiz.

  36. misty1212
    • one year ago
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    ok well is it really \[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]?

  37. misty1212
    • one year ago
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    because that equation has no real solutions, maybe there is a typo there

  38. anonymous
    • one year ago
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    yes. that's how it's written on my problem

  39. anonymous
    • one year ago
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    well one of the answers is there is no solution

  40. misty1212
    • one year ago
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    then either you are supposed to come up with two ugly complex solutions, or say "no solution"

  41. anonymous
    • one year ago
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    so you sorta answered my question

  42. misty1212
    • one year ago
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    ok fine in any case you really want to multiply by 15 first and start with \[6x^2-15x+19=0\] then, when you use the quadratic formula, you will see that there is no answer

  43. misty1212
    • one year ago
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    you do not want to use decimals you do not want to use fractions you want to work with integers only

  44. anonymous
    • one year ago
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    okay, thank you

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