2) 2/5x^2 -x+ 19/15 =0

- anonymous

2) 2/5x^2 -x+ 19/15 =0

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- anonymous

lol

- just_one_last_goodbye

anyways lets see how i can help

- just_one_last_goodbye

is the first 2 part of the equation or no?

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## More answers

- anonymous

\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]

- anonymous

I hope that makes it better

- just_one_last_goodbye

Much better ^-^

- anonymous

So I know
A= 2/5
B= -1
C= 19/15

- just_one_last_goodbye

Decimal answer correct?

- anonymous

yes

- just_one_last_goodbye

and Solving for x?

- just_one_last_goodbye

x = 1.455485

- anonymous

it says
"Use the quadratic formula to solve the equation."
"A. The solution set is ____"
(simplify your answer. type an exact answer, ysing radicals as needed. Use intefers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)
"B. the solution is (emptyset)"

- just_one_last_goodbye

~eats pizza while waiting~

- anonymous

lol my b

- just_one_last_goodbye

~passes skittles~

- anonymous

omg. skittles with coffee

- anonymous

yes

- just_one_last_goodbye

^

- just_one_last_goodbye

Oh quadratic thought it was a normal equation sorry

- anonymous

lol, the only unit i have left is quadratic and I haven't done it in 2 years

- just_one_last_goodbye

hmm idk it's not giving me an answer

- anonymous

okay it's okay, let's move on to the next question?

- just_one_last_goodbye

sure

- anonymous

.6x^2 = 1.2x+0.6

- anonymous

\[0.6x^2-1.2x-0.6=0\]

- just_one_last_goodbye

wait is it an addition problem or subtraction?

- anonymous

I just flipped it so it's in standard form. it's still quadratic. just now it's all on one side.

- anonymous

...

- just_one_last_goodbye

Open this attachment up, It should help ^-^

##### 1 Attachment

- anonymous

what site did you use?

- misty1212

HI!!

- just_one_last_goodbye

. - . . _ .

- misty1212

\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\] is annoying
multiply by 15 and get
\[6x^2-15x+19=0\] then it will be much easier

- misty1212

you can use the quadratic formula or if you are a factoring wiz you can try that

- anonymous

yeah. I'm on here, asking for help. I'm not a factoring wiz.

- misty1212

ok well is it really
\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]?

- misty1212

because that equation has no real solutions, maybe there is a typo there

- anonymous

yes. that's how it's written on my problem

- anonymous

well one of the answers is there is no solution

- misty1212

then either you are supposed to come up with two ugly complex solutions, or say "no solution"

- anonymous

so you sorta answered my question

- misty1212

ok fine
in any case you really want to multiply by 15 first and start with
\[6x^2-15x+19=0\] then, when you use the quadratic formula, you will see that there is no answer

- misty1212

you do not want to use decimals
you do not want to use fractions
you want to work with integers only

- anonymous

okay, thank you

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