anonymous
  • anonymous
2) 2/5x^2 -x+ 19/15 =0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
lol
just_one_last_goodbye
  • just_one_last_goodbye
anyways lets see how i can help
just_one_last_goodbye
  • just_one_last_goodbye
is the first 2 part of the equation or no?

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More answers

anonymous
  • anonymous
\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]
anonymous
  • anonymous
I hope that makes it better
just_one_last_goodbye
  • just_one_last_goodbye
Much better ^-^
anonymous
  • anonymous
So I know A= 2/5 B= -1 C= 19/15
just_one_last_goodbye
  • just_one_last_goodbye
Decimal answer correct?
anonymous
  • anonymous
yes
just_one_last_goodbye
  • just_one_last_goodbye
and Solving for x?
just_one_last_goodbye
  • just_one_last_goodbye
x = 1.455485
anonymous
  • anonymous
it says "Use the quadratic formula to solve the equation." "A. The solution set is ____" (simplify your answer. type an exact answer, ysing radicals as needed. Use intefers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) "B. the solution is (emptyset)"
just_one_last_goodbye
  • just_one_last_goodbye
~eats pizza while waiting~
anonymous
  • anonymous
lol my b
just_one_last_goodbye
  • just_one_last_goodbye
~passes skittles~
anonymous
  • anonymous
omg. skittles with coffee
anonymous
  • anonymous
yes
just_one_last_goodbye
  • just_one_last_goodbye
^
just_one_last_goodbye
  • just_one_last_goodbye
Oh quadratic thought it was a normal equation sorry
anonymous
  • anonymous
lol, the only unit i have left is quadratic and I haven't done it in 2 years
just_one_last_goodbye
  • just_one_last_goodbye
hmm idk it's not giving me an answer
anonymous
  • anonymous
okay it's okay, let's move on to the next question?
just_one_last_goodbye
  • just_one_last_goodbye
sure
anonymous
  • anonymous
.6x^2 = 1.2x+0.6
anonymous
  • anonymous
\[0.6x^2-1.2x-0.6=0\]
just_one_last_goodbye
  • just_one_last_goodbye
wait is it an addition problem or subtraction?
anonymous
  • anonymous
I just flipped it so it's in standard form. it's still quadratic. just now it's all on one side.
anonymous
  • anonymous
...
just_one_last_goodbye
  • just_one_last_goodbye
Open this attachment up, It should help ^-^
1 Attachment
anonymous
  • anonymous
what site did you use?
misty1212
  • misty1212
HI!!
just_one_last_goodbye
  • just_one_last_goodbye
. - . . _ .
misty1212
  • misty1212
\[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\] is annoying multiply by 15 and get \[6x^2-15x+19=0\] then it will be much easier
misty1212
  • misty1212
you can use the quadratic formula or if you are a factoring wiz you can try that
anonymous
  • anonymous
yeah. I'm on here, asking for help. I'm not a factoring wiz.
misty1212
  • misty1212
ok well is it really \[\frac{ 2 }{ 5 }x^2-x+\frac{ 19 }{ 15 }=0\]?
misty1212
  • misty1212
because that equation has no real solutions, maybe there is a typo there
anonymous
  • anonymous
yes. that's how it's written on my problem
anonymous
  • anonymous
well one of the answers is there is no solution
misty1212
  • misty1212
then either you are supposed to come up with two ugly complex solutions, or say "no solution"
anonymous
  • anonymous
so you sorta answered my question
misty1212
  • misty1212
ok fine in any case you really want to multiply by 15 first and start with \[6x^2-15x+19=0\] then, when you use the quadratic formula, you will see that there is no answer
misty1212
  • misty1212
you do not want to use decimals you do not want to use fractions you want to work with integers only
anonymous
  • anonymous
okay, thank you

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