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anonymous

  • one year ago

Which linear function represents the line given by the point-slope equation y + 1 = –3(x – 5)? f(x) = –3x – 6 f(x) = –3x – 4 f(x) = –3x + 16 f(x) = –3x + 14

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  1. Mehek14
    • one year ago
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    first use distribution \(-3(x-5)\\-3*x=-3x\\-3*-5=15\\y+1=-3x+15\)

  2. Mehek14
    • one year ago
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    what is 15 - 1 @jonestyrese15

  3. anonymous
    • one year ago
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    i think the answer is d

  4. Mehek14
    • one year ago
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    you are correct ^_^

  5. Imtiaz7
    • one year ago
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    f(x)= -3x+14

  6. Mehek14
    • one year ago
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    @Imtiaz7 sort of late :P

  7. anonymous
    • one year ago
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    can u help me with one more

  8. Mehek14
    • one year ago
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    sure

  9. anonymous
    • one year ago
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    The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use? When Harold wrote his equation, the point he used was (7, 3). When Harold wrote his equation, the point he used was (0, 7). When Harold wrote his equation, the point he used was (7, 0). When Harold wrote his equation, the point he used was (3, 7).

  10. Imtiaz7
    • one year ago
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    Yup :P@Mehek14

  11. Mehek14
    • one year ago
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    you have to find which point is on the line y = 3(x – 7)

  12. Mehek14
    • one year ago
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    which is (7,0)

  13. anonymous
    • one year ago
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    so c

  14. Mehek14
    • one year ago
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    yes

  15. anonymous
    • one year ago
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  16. anonymous
    • one year ago
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    Which equations and/or functions represent the graphed line? Check all that apply. f(x) = 0.2x - 4 f(x) = 0.5x + 2 f(x) = x + 2 y – 3 = (x – 2) y – 1 = 0.5(x + 2)

  17. Mehek14
    • one year ago
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    f(x) = 0.5x + 2

  18. anonymous
    • one year ago
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    thts the only one

  19. Mehek14
    • one year ago
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    y – 1 = 0.5(x + 2)

  20. Mehek14
    • one year ago
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    those 2

  21. anonymous
    • one year ago
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    ok

  22. anonymous
    • one year ago
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    Which linear function represents the line given by the point-slope equation y + 1 = –3(x – 5)? f(x) = –3x – 6 f(x) = –3x – 4 f(x) = –3x + 16 f(x) = –3x + 14

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