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first use distribution \(-3(x-5)\\-3*x=-3x\\-3*-5=15\\y+1=-3x+15\)
i think the answer is d
you are correct ^_^
can u help me with one more
The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use? When Harold wrote his equation, the point he used was (7, 3). When Harold wrote his equation, the point he used was (0, 7). When Harold wrote his equation, the point he used was (7, 0). When Harold wrote his equation, the point he used was (3, 7).
you have to find which point is on the line y = 3(x – 7)
which is (7,0)
Which equations and/or functions represent the graphed line? Check all that apply. f(x) = 0.2x - 4 f(x) = 0.5x + 2 f(x) = x + 2 y – 3 = (x – 2) y – 1 = 0.5(x + 2)
f(x) = 0.5x + 2
thts the only one
y – 1 = 0.5(x + 2)
Which linear function represents the line given by the point-slope equation y + 1 = –3(x – 5)? f(x) = –3x – 6 f(x) = –3x – 4 f(x) = –3x + 16 f(x) = –3x + 14