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anonymous

  • one year ago

Find the limit of the function algebraically. limit as x approaches negative six of quantity x squared minus thirty six divided by quantity x plus six.

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  1. anonymous
    • one year ago
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    I just need to know if I can use direct substitution right away or if there are any step I need to do before that

  2. anonymous
    • one year ago
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    can you try writing it with the equation?

  3. anonymous
    • one year ago
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    sorry its hard for me to visualize the problem purely with words

  4. anonymous
    • one year ago
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    http://prntscr.com/80cyqz

  5. anonymous
    • one year ago
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    \[\lim_{x \rightarrow -6}\frac{ x^2-36 }{ x+6 } = \frac{ (x-6)(x+6) }{ x+6 }\]now try to continue from here

  6. anonymous
    • one year ago
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    x-6

  7. anonymous
    • one year ago
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    yea

  8. Loser66
    • one year ago
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    just small mistake \(\lim_{x \rightarrow -6}\frac{ x^2-36 }{ x+6 } =lim_{x\rightarrow -6}\frac{ (x-6)(x+6) }{ x+6 }=\color{red}{lim_{x\rightarrow -6}}x-6\) Then replace x =-6 in It is small but very important because lim (something) = value, not = x -6

  9. anonymous
    • one year ago
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    thanks

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