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mathmath333
 one year ago
Set Theory.
mathmath333
 one year ago
Set Theory.

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align}& \normalsize \text{Let }\ A,B\ \text{and }C\ \text{be three sets. } \hspace{.33em}\\~\\ & \normalsize \text{If}\ A\in B\ \text{and}\ B\subset C,\hspace{.33em}\\~\\ & \normalsize \text{Is it true that }\ A\subset C\ ?\hspace{.33em}\\~\\ \end{align}}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0I have to show it with example

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0every element of A is also an element of B, and every element of B is also an element of C, so every element of A is an element of C

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0Wait my book says it it false

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0also this example works well: dw:1438616949711:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0wait let me show my book proof

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2wwwwwwwwwwwat?? hahaha,.... then I failed!!

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438617127714:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Yes!! it is perfect. I am sorry for my careless!! \(\in \neq \subset\)

freckles
 one year ago
Best ResponseYou've already chosen the best response.0A that little e thing B means A is an element of B and no a set can't be a element of another set it can be a subset of another set

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0the same of @Loser66, I'm very sorry @mathmath333

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2hihihi.,.... no worry, everybody has mistake.
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