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HelloKitty17

  • one year ago

Solve U = 0.5CV2 for C. C = U over 2V C = U over 2V squared C = 2U over V C = 2U over V squared

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  1. anonymous
    • one year ago
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    \[U=0.5CV^2\] looks right?

  2. HelloKitty17
    • one year ago
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    @jcoury

  3. OregonDuck
    • one year ago
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    yes

  4. anonymous
    • one year ago
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    idk on this one

  5. anonymous
    • one year ago
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    multiply by 2 on both sides

  6. anonymous
    • one year ago
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    can i ask you guys some questions when ur done

  7. HelloKitty17
    • one year ago
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    then

  8. OregonDuck
    • one year ago
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    i will give 3 medals for the answer, sure

  9. anonymous
    • one year ago
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    \[U \times 2 = 2 \times 0.5CV^2\]

  10. anonymous
    • one year ago
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    what do ya get?

  11. anonymous
    • one year ago
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    this one is easy, trust me

  12. OregonDuck
    • one year ago
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    \[1.0CV ^{2}\]

  13. HelloKitty17
    • one year ago
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    I don't understand how to do this that is why I asked

  14. anonymous
    • one year ago
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    \[2U=CV^2\]

  15. OregonDuck
    • one year ago
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    ks that the answer?

  16. anonymous
    • one year ago
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    now divide both sides by V^2

  17. anonymous
    • one year ago
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    \[\frac{ 2U }{ V^2 } = \frac{ CV^2 }{ V^2 }\]

  18. OregonDuck
    • one year ago
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    is that the answer?

  19. HelloKitty17
    • one year ago
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    so what is the answer?!

  20. anonymous
    • one year ago
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    @jcoury just ask i have no problem helping ppl 2 or 3 at once

  21. anonymous
    • one year ago
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    nah, you need to simplify it

  22. anonymous
    • one year ago
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    k hold on

  23. anonymous
    • one year ago
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    \[\frac{ 2U }{ V^2 }=C\]

  24. anonymous
    • one year ago
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    thats your answeer

  25. anonymous
    • one year ago
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    @saseal check your messages

  26. anonymous
    • one year ago
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    ok

  27. anonymous
    • one year ago
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    1 Attachment
  28. anonymous
    • one year ago
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    guys its Saseal's birthday today!

  29. OregonDuck
    • one year ago
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    Happy Birthday @saseal

  30. anonymous
    • one year ago
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    ty

  31. OregonDuck
    • one year ago
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    :)

  32. anonymous
    • one year ago
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    lol

  33. HelloKitty17
    • one year ago
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    HAPPY B-DAY!!! How old are you?!

  34. anonymous
    • one year ago
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    24

  35. HelloKitty17
    • one year ago
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    Sweet!!! Any plans for today?!

  36. anonymous
    • one year ago
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    @saseal https://www.youtube.com/watch?v=nX6N2tgLmaQ

  37. anonymous
    • one year ago
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    watch it

  38. anonymous
    • one year ago
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    lol

  39. anonymous
    • one year ago
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    i just felt that was appropriate

  40. anonymous
    • one year ago
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    i have a few more questions can i ask them?

  41. anonymous
    • one year ago
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    maybe 1 or 2 fast ones, i have some engineering problems to do also :(

  42. anonymous
    • one year ago
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    okay hold on

  43. anonymous
    • one year ago
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  44. anonymous
    • one year ago
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    and if you have time

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  45. anonymous
    • one year ago
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    i think i did the 2nd question wrong earlier

  46. anonymous
    • one year ago
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    so c for 2 right

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