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anonymous

  • one year ago

Solve the following system of equations and show all work. y = 2x2 y = –3x −1

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  1. anonymous
    • one year ago
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    @mathmate

  2. anonymous
    • one year ago
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    \[y=2.x^{2}\]?

  3. anonymous
    • one year ago
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    no y=2x^2

  4. triciaal
    • one year ago
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    set the y's equal and solve for x then substitute this value in one of the expressions for y to get the value of y

  5. mathmate
    • one year ago
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    Use comparison: y=2x^2 y=-3x-1 Since they are both y, they are equal, so put 2x^2=-3x-1, or transposing, solve 2x^2+3x+1=0 (by factoring) to solve the problem.

  6. triciaal
    • one year ago
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    |dw:1438619700713:dw|

  7. anonymous
    • one year ago
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    so then would it be 2x^2+3x+1?

  8. triciaal
    • one year ago
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    equation must be equal to something

  9. anonymous
    • one year ago
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    \[2.x^{2}+3x+1=0\]

  10. anonymous
    • one year ago
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    2x^2+3x+1=0

  11. anonymous
    • one year ago
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    then we could factor right?

  12. triciaal
    • one year ago
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    yes solve for x

  13. anonymous
    • one year ago
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    um then i got 1/2 and -1??

  14. triciaal
    • one year ago
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    |dw:1438619899819:dw|

  15. anonymous
    • one year ago
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    And then to get the points would we have to plug them back in?

  16. triciaal
    • one year ago
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    |dw:1438620195735:dw|

  17. anonymous
    • one year ago
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    so the x intercepts would be -1/2, and -1 correct?

  18. anonymous
    • one year ago
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    and when i plugged it back in, i got (-0.5,0.5) (-1,2)

  19. triciaal
    • one year ago
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    checking for arithmetic error above

  20. anonymous
    • one year ago
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    hahah okay:)

  21. anonymous
    • one year ago
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    thanks for all ur help!

  22. triciaal
    • one year ago
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    welcome

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