The number of toys owned by eight classmates is shown below:
4, 3, 4, 5, 6, 6, 8, 4
Part A: What is the mean of the data? Show your work. (4 points)
Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

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- welshfella

Par A the mean is the sum of the 8 numbers divided by 8.

- anonymous

so five

- anonymous

i need help on part b

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## More answers

- welshfella

yes

- welshfella

Give me a second on that one. My memory is a bit hazy on that so i need to check something.

- anonymous

ok

- welshfella

you take each value and find the difference between it and the mean.
for example the first value 4 the difference is mean-4 = 5-4 = 1

- anonymous

i dont get that

- welshfella

Do that with each value (in a table if you like) and add these computed differences up Divide the result by 8 and you have the mean absolute deviation.

- welshfella

|dw:1438622310370:dw|

- anonymous

can you help me that

- anonymous

so i have to divide 8 by 5 4 and 1

- welshfella

|dw:1438622377903:dw|

- welshfella

get the idea?

- anonymous

no

- anonymous

|dw:1438622579346:dw|

- anonymous

i dont get that

- welshfella

you are subtracting each of the 8 numbers from the mean (which is 5) or if the number is greater than 5 you subtract 5 from the number.

- anonymous

so 10

- welshfella

|dw:1438622689861:dw|

- anonymous

ok 10

- welshfella

yes 10 is correct

- welshfella

now divide 10 by 8 and you have the mean absolute deviation.

- anonymous

1.25

- welshfella

correct

- welshfella

it gives a measure of the spread of the numbers around the mean.

- anonymous

ok can you help me with another one

- welshfella

I'll have to come back in a bit

- anonymous

so no

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