anonymous
  • anonymous
Find the roots of the function f(x)=(x-8)^2-1
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
What do you think?
anonymous
  • anonymous
i have no clue honestly
triciaal
  • triciaal
to find the root set the function = 0 and solve for x

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More answers

anonymous
  • anonymous
\[(x-8)^{2}-1 = x^2-16x+64-1=x^{2}-16x+63 = 0\]
anonymous
  • anonymous
ok so i would do (x-8)^2-1=0?
anonymous
  • anonymous
Follow ginochen
anonymous
  • anonymous
Solve for \( \large x^{2}-16x+63 = 0\)
triciaal
  • triciaal
|dw:1438622778795:dw|
anonymous
  • anonymous
Or triciaal way
anonymous
  • anonymous
ty Tricia;; that heped me out alot and i got it right
anonymous
  • anonymous
i hate math so ty u guys for the help
triciaal
  • triciaal
same as above but I applied the difference of 2 squares to make it faster
triciaal
  • triciaal
|dw:1438623031873:dw|
anonymous
  • anonymous
ok so with the the equation so with the equation f(x)=2x^2-12 i would do the same thng right
triciaal
  • triciaal
12 is not a perfect square
triciaal
  • triciaal
to solve for x yes make the function = 0
triciaal
  • triciaal
|dw:1438623223197:dw|
anonymous
  • anonymous
so the answers would be x=-6 and x=+6
triciaal
  • triciaal
|dw:1438623398726:dw|

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