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anonymous

  • one year ago

In the reaction below, iodine gas, I2 (g), is violet in color, while hydrogen gas, H2 (g), and hydrogen iodide, HI (g), are both colorless. When H2 (g) and I2 (g) are combined in a closed flask, the violet color decreases but never disappears completely. Which of the following explains what is happening when the color appears to stop changing? H2 (g) + I2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. 2HI (g)

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  1. anonymous
    • one year ago
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    The forward reaction, H2 (g) + I2 (g) yields 2HI (g), is proceeding too slowly for any HI (g) to form. The reverse reaction, 2HI (g) yields H2 (g) + I2 (g), is occurring at the same rate as the forward reaction. The product of the original reaction is reacting with the I2 (g), forming a gas with properties similar to I2 (g). The reaction has reached completion, and H2 (g) was the limiting reactant, leaving unreacted I2 (g) behind.

  2. anonymous
    • one year ago
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    @JoannaBlackwelder

  3. anonymous
    • one year ago
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    a?

  4. JoannaBlackwelder
    • one year ago
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    When a reaction reaches equilibrium, the forward reaction occurs at the same rate as the reverse reaction. The reaction doesn't stop completely.

  5. anonymous
    • one year ago
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    oh so c?

  6. JoannaBlackwelder
    • one year ago
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    No, b

  7. anonymous
    • one year ago
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    oh ok

  8. JoannaBlackwelder
    • one year ago
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    That is what the |dw:1438629418042:dw| means

  9. anonymous
    • one year ago
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    ok

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