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anonymous

  • one year ago

We perform the experiment "Toss two dice". What is the probability of the event "no 3 appears on either face. answers 10/36 11/36 1/36 and 25/36

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  1. anonymous
    • one year ago
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    Do you know it

  2. anonymous
    • one year ago
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    how many ways can you have no 3 on the first face?

  3. anonymous
    • one year ago
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    For one die

  4. anonymous
    • one year ago
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    1/6

  5. anonymous
    • one year ago
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    there are 5 ways not to get a 3 should be 5/6

  6. anonymous
    • one year ago
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    right

  7. anonymous
    • one year ago
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    ok so 5/6

  8. anonymous
    • one year ago
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    similarly, there is a 5/6 chance for the second die , not to get a 3

  9. anonymous
    • one year ago
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    Now you multiply 5/6 * 5/6

  10. anonymous
    • one year ago
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    31.36

  11. anonymous
    • one year ago
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    no 25/36

  12. anonymous
    • one year ago
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    in symbols P( 1st die is not 3 & 2nd die is not 3) = P( 1st die is not 3) * P( 2nd die is not 3)

  13. anonymous
    • one year ago
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    correct

  14. anonymous
    • one year ago
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    because the events are indepenent

  15. anonymous
    • one year ago
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    so that's the answer and thank you very much i m not good at math

  16. anonymous
    • one year ago
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    your welcome

  17. anonymous
    • one year ago
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    ok so if i roll a three i would do 3/6

  18. campbell_st
    • one year ago
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    I think this questions needs to state what numbers are on the dice before asking for the probability of no 3 if 3 isn't on the dice the the probability would be zero

  19. anonymous
    • one year ago
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    thanks but i already got the answer srry

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