We perform the experiment "Toss two dice". What is the probability of the event "no 3 appears on either face. answers 10/36 11/36 1/36 and 25/36

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We perform the experiment "Toss two dice". What is the probability of the event "no 3 appears on either face. answers 10/36 11/36 1/36 and 25/36

Mathematics
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how many ways can you have no 3 on the first face?
For one die

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Other answers:

1/6
there are 5 ways not to get a 3 should be 5/6
right
ok so 5/6
similarly, there is a 5/6 chance for the second die , not to get a 3
Now you multiply 5/6 * 5/6
31.36
no 25/36
in symbols P( 1st die is not 3 & 2nd die is not 3) = P( 1st die is not 3) * P( 2nd die is not 3)
correct
because the events are indepenent
so that's the answer and thank you very much i m not good at math
your welcome
ok so if i roll a three i would do 3/6
I think this questions needs to state what numbers are on the dice before asking for the probability of no 3 if 3 isn't on the dice the the probability would be zero
thanks but i already got the answer srry

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