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anonymous
 one year ago
Find the instantaneous velocity and speed at time 5 secs when v(t) = t2 – 9t + 18 and s(0) = 1
anonymous
 one year ago
Find the instantaneous velocity and speed at time 5 secs when v(t) = t2 – 9t + 18 and s(0) = 1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i figured i would just ave to find the acceleration (which is just the derivative of v(t)) and then plug five into that but i did that and got it wrong

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Why would you find acceleration when it's asking for velocity, just plug in 5 for your velocity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its asking for the instantaneous velocity doesn't that mean the tangent?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Are you sure it's not suppose to be s(t)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i am also given s(0) so i can just find s(t)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You're given the instantaneous velocity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so then v(5) = 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay and for the speed i just find s(t) and plug five into that right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1s(t) is the position

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1speed is just scalar

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so then speet(t)=2 ?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, speed is just the magnitude or the velocity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay lovely ! thank you very much!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We could find the position to s(t), by integrating, \[v(t) = t^29t+18 \implies \frac{ ds }{ dt } = t^29t+18\]\[\int\limits ds = \int\limits (t^29t+18) dt = s(t) = \frac{ t^3 }{ 3 }\frac{ 9t^2 }{ 2 }+18t+C \]
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