Find the time intervals for v(t) = t^2 - 9t + 18 when the particle is
a.going faster
b.slowing down

Find the time intervals for v(t) = t^2 - 9t + 18 when the particle is
a.going faster
b.slowing down

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so iv go
a. (4.5 , infinity)
b. (-infinity , 4.5)
but apparently their is 2 intervals for each

see if the graph helps
|dw:1438632617992:dw|

I think you also need to look at the points where the velocity is becoming 0
(x intercepts)

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